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2 years ago

Someone help me with this, it’s due today

Mathematics

2 answers:

Anna [14]2 years ago

4 0

Answer:

use points (1,1) and (0,2) for the rise and run

slope is 1

I hope this is good enough:

Ket [755]2 years ago

3 0

Answer:2\2

Step-by-step explanation: you can see it at 2\2

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Help me please I have no idea on how to do this. Thanks

andriy [413]

1) P=2w +2l
46=2w +14
32=2w
16= w or width

2) A=lw
A=7 x 12
A= 84

3) A= 12 x 21
A= 252

6 0

2 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

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3 years ago

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Help me ASAP for this question

ludmilkaskok [199]

Answer:

Your answer is 7

Hope this helps!

Step-by-step explanation:

You plug 14 in for x then just do 14-7 and you will get 7

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2 years ago

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The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is

svetoff [14.1K]

The answer b= 2h
the angle opposite to its base is a
so sina = b/2h= b/b=1
the answer is <span>b) 1</span>

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3 years ago

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At 4:00 AM, the temperature is – 12 °F. If the temperature drops 3 °F per hour, what will the temperature be at 6:00 AM?

Scilla [17]

The answer would be -18°F at 6AM
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2 years ago

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