Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
AAS rule can prove these triangles are congruent cuz u see two angles are marked as equal to each other but the side that’s overlapped on each other(the line the triangles are sharing) shows that the side is equal length to each other.
Answer:

Step-by-step explanation:
We are given the following expression in the question:

a)

which is not equivalent to the given expression.
b)

which is equivalent to the given expression
c)

which is equivalent to the given expression.
d)

which is not equivalent to the given expression.
e)

which is equivalent to the given expression.