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Yakvenalex [24]
3 years ago
11

If a basketball court is 94 feet long and 50 feet wide, what is the area of a basketball court?

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0
94 x 50 = 4700 square feet
dem82 [27]3 years ago
7 0

Answer:

4700

Step-by-step explanation:

To find the area, the formula is to multiply the width and the length. That is what I did and got 47 hundred

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X/62+89=92 !!!! plz quick
elena-s [515]

To solve an algebraic equation, we need to get x by itself. We can start to do that by multiplying each side of the equation by 62 (to remove the denominator of x).


x + 89(62) = 92 * 62


Simplify


x = 92 * 62 - 89 * 62


Now we can factor out 62


x = 62 (92 - 89)


Now we can simplify the parenthesis


x = 62 * 3


x = 186

5 0
3 years ago
Tickets to a concert cost $2 for children and $5 for adults. If 630 people attended the concert and the ticket sales totaled $2,
sergeinik [125]
A) C + A = 630
B) 2C + 5A = 2,910  Multiplying A by -2
A) -2C -2A = -1,260 Then adding it to B
B) 2C + 5A = 2,910 
3A = 1,650
A = 550

A) C + 550 = 630
Children's tickets = 80



8 0
3 years ago
Read 2 more answers
Can someone plz help me with this it’s due rn
Rama09 [41]
20, 20, 20, 30, 20
Tip for rounding nearest 10th: if the 2nd number is above 5 it’s the one above, if it’s below 5 it’s the one below.
8 0
3 years ago
Calculate the distance between the points F=(-2,1) and A=(4,-2) in the coordinate plane. Round your answer to the nearest hundre
Anton [14]

Answer:

The distance between F and A is approximately 6.71 units.

Step-by-step explanation:

To find the distance between any two points, we can consider using the distance formula. Recall that:

\displaystyle d  = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let F(-2, 1) be (<em>x</em>₁, <em>y</em>₁) and A(4, -2) be (<em>x</em>₂, <em>y</em>₂).

Substitute and evaluate:

\displaystyle \begin{aligned} FA &= \sqrt{((4) - (-2))^2 + ((-2) - (1)^2} \\ \\&=\sqrt{(6)^2 + (-3)^2} \\ \\&=\sqrt{36 + 9} \\ \\ &= \sqrt{45} \\ \\ &= 3\sqrt{5}\\ \\&\approx 6.71\text{ units}  \end{aligned}

In conclusion, the distance between <em>F</em> and <em>A</em> is approximately 6.71 units.

8 0
2 years ago
You and your friend are planning to walk across an old bridge. The bridge can hold at most 1000 pounds. The total weight of the
valentina_108 [34]
No, because if you add both of you and your friend's weight, it becomes 338. if you add that to 675, it becomes 1,013 lbs., which is over 1,000 lbs.
3 0
3 years ago
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