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Georgia [21]
3 years ago
13

What are beats?

Physics
1 answer:
Annette [7]3 years ago
8 0
In acoustics, a beat is an interference pattern between two sounds of slightly different frequencies, perceived as a periodic variation in volume whose rate is the difference of the two frequencies. With tuning instruments that can produce sustained tones, beats can be readily recognized. So I believe D.
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A single strain gage has a nominal resistance of 120 ohm. For a quarter bridge with 120 ohm fixed resistors, strain gauge factor
natita [175]

Answer:

Output voltage is 1.507 mV

Solution:

As per the question:

Nominal resistance, R = 120\Omega

Fixed resistance, R = 120\Omega

Gauge Factor, G.F = 2.01

Supply Voltage, V_{s} = 3\ V

Strain, \epsilon = 1000\times 10^{-6}\ strain

Now,

To calculate the output voltage, V_{o}:

WE know that strain is given by:

\epsilon = \frac{(R + R')^{2}V_{o}}{RR'V_{s}\times G.F}

Thus

V_{o} = \frac{RR'V_{s}\epsilon \times G.F}{(R + R')^{2}}

Now, substituting the suitable values in the above eqn:

V_{o} = \frac{120\times 120\times 3\times 1000\times 10^{-6}\times 2.01}{(120 + 120)^{2}}

V_{o} = 1.507\ mV

6 0
4 years ago
An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1=584 kg, m2=838 kg, and m3=322 kg have blocke
Elena-2011 [213]

Answer:

Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N

Explanation:

Total force required = Mass x Acceleration,

F = ma

Here we need to consider the system as combine, total mass need to be considered.

Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg

We need to accelerate the group of rocks from the road at 0.250 m/s²

That is acceleration, a = 0.250 m/s²

Force required, F = ma = 1744 x 0.25 = 436 N

Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N

8 0
3 years ago
¿Cuál será la potencia de una bombilla conectada a una red de energía eléctrica de 440V, si la corriente que circula por el circ
goblinko [34]

Answer:

La potencia de la bombilla es de 1056 W.

Explanation:

La potencia de la bombilla se puede calcular usando la siguiente ecuación:

P = I*V

En donde:

P: es la potencia

I: es la corriente = 2,4 A

V: es la diferencia de potencial = 440 V

Entonces, la potencia es:

P = I*V = 2,4 A*440 V = 1056 W

Por lo tanto, la potencia de la bombilla es de 1056 W.

Espero que te sea de utilidad!

3 0
3 years ago
A missile is moving 1350 m/s at a 25.0 angle
murzikaleks [220]
I will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes
4 0
3 years ago
A heavenly body in another's shadow is ____
Alex_Xolod [135]
<span>It is called a lunar eclipse</span>
8 0
4 years ago
Read 2 more answers
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