Given the distance between 7V equipotential and the 5V at point B is .9cm and the distance between the 3V equipotential and the
1 answer:
Answer:
Electric field, E = 2.22 V/cm
Explanation:
Given that,
The distance between 7 V equipotential and 5 V at point B is 0.9 cm. The relation between electric field and electric potential is given by :
E = 2.22 V/cm
So, the magnitude of the electric field at point B is 2.22 V/cm. Hence, this is the required solution.
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Answer:
Increasing speed.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.