Electricity. Ruler. 69. N.
Answer:
3 seconds
Explanation:
Applying,
Applying,
v = u±gt................ Equation 1
Where v = final velocity, u = initial velocity, t = time, g = acceleration due to gravity.
From the question,
Given: v = 0 m/s ( at the maximum height), u = 30 m/s
Constant: g = -10 m/s
Substitute these values into equation 1
0 = 30-10t
10t = 30
t = 30/10
t = 3 seconds
Answer:
a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).
Explanation:
a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:
42 m/s, positive direction (to the east).
b) The relative velocity of Car B as seen by the drive of Car A is:
42 m/s, negative direction (to the west).
Answer:
83.3 kHz
Explanation:
The frequency of a waveform is equal to the reciprocal of its period:
where
f is the frequency
T is the period
In this problem, we have
so, the frequency of the waveform is
And by converting into kiloHertz,
The direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.
<h3>
How to determine electric field direction in a metal block?</h3>
The charge always remain on outer surface of metal and inside the metal block, the net electric field is zero. But due to dipole there is an electric field at the center of metal block i.e. at point R along direction line 1.
Now, to make make the net electric field zero at center, the electric field by the charge in and on the metal block must be equal in magnitude to that of electric field due to dipole at point R and in opposite direction to that of the net electric field at at R due to dipole.
The electric field by the charge in and on the metal block will be making 180° angle to the electric field due to dipole at point R.
Hence the direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.
To know more about electric field, click on brainly.com/question/11509296
#SPJ4
