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Vlad [161]
2 years ago
14

¿Cuál será la potencia de una bombilla conectada a una red de energía eléctrica de 440V, si la corriente que circula por el circ

uito de la bombilla es de 2,4A?
Physics
1 answer:
goblinko [34]2 years ago
3 0

Answer:

La potencia de la bombilla es de 1056 W.

Explanation:

La potencia de la bombilla se puede calcular usando la siguiente ecuación:

P = I*V

En donde:

P: es la potencia

I: es la corriente = 2,4 A

V: es la diferencia de potencial = 440 V

Entonces, la potencia es:

P = I*V = 2,4 A*440 V = 1056 W

Por lo tanto, la potencia de la bombilla es de 1056 W.

Espero que te sea de utilidad!

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Two samples of water are mixed together.
horrorfan [7]

Let the cold water go up x degrees.

Let the hot water go down 100 - x degrees.

The formula for heat exchange is m*c*delta t

Givens

Ice

deltat = x

m = 0.50 kg

c = 4.18

Hot water

deltat = 100 - x

m = 1.5 kg

c = 4.18

Formula

The heat up = heat down

0.50 * c * x = 1.5 * c * (100 - x)            Divide both sides by c

Solution

0.50 *x = 1.5*(100 - x)                          Remove the brackets.

0.5x = 150 - 1.5x                                  Add 1.5x to both sides.

0.5x + 1.5x = 150 - 1.5x + 1.5x             Combine like terms  

2x = 150                                               Divide by 2

x = 75

Answer

A

6 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
How are the land area and the oceans affected during an ice age
amm1812
The land was frozen everywhere and a part of the ocean froze over to create a bridge between two countries. Some people may disagree with me over the ice bridge, though.
3 0
3 years ago
Read 2 more answers
А geostationary satellite moves in an orbit of radius 6300km. Calculate the speed with which it moves in the orbit [π=22÷7]​
azamat

Answer:

15.3 m/s

Explanation:

Radius of orbit= 6400+6300 = 12700 km

Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m

Now,

       Speed= Distance / Time

                  = 79796.45*10^3/(24*60*3600)

                  = 15.3 m/s

4 0
2 years ago
Find the velocity of a baseball thrown 78 m from third base to first base in 30 sec​
ankoles [38]

Answer:

V=2.6m/s

Explanation:

velocity=Distance/time

V=78/30=2.6m/s

3 0
2 years ago
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