Fill in the blank with a number to make the expression a perfect square.

Mathematics

1 answer:

Sati [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Substituting 16 will make the expression valid and correct since the square of -4 is 16 and the addition of it is -8.

$v^2-8v+16=(v-4)^2$

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Solve each equations for x. How are these equations similar?

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If you multiply a. by x it is equivalent to b.
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You roll a number cube. What is the probability that you roll an even number or a number less than 5?

NISA [10]

Let’s first see the probability of landing an even number. We have 6 sides, and 3 are labeled with an even number. So our chances of rolling a number cube are 3/6 (or 1/2 when simplified).

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A hot air balloon rises 9 meters every 3 seconds. A blimp rises 5 meters every two seconds. Which will take the shortest time to

malfutka [58]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

If this particular arithmetic sequence, a7=34 and a15=74. What is the value of a21

Ilya [14]

This is an arithmetic sequence, meaning, to get the next term, you simply add some value to the current one, namely the "common difference" "d".

now, we know the 17th term is 34, let's go to the 15term then

34 + d
34 + d + d
34 + d + d + d
34 + d + d + d + d
34 + d + d + d + d + d
34 + d + d + d + d + d + d
34 + d + d + d + d + d + d + d
34 + d + d + d + d + d + d + d + d

now, notice, we got to the 15th term, which is 34 + d + d + d + d + d + d + d + d, or namely 34 + 8d, it just so happen we know is 74, therefore,

$\bf 34+8d=74\implies 8d=40\implies d=\cfrac{40}{8}\implies \boxed{d=5}$

ok, now that we know what the common difference is, let's find the first term in the sequence using the 7th term of 34,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=5\\
a_7=34
\end{cases}
\\\\\\
a_7=a_1+(7-1)5\implies 34=a_1+(7-1)5
\\\\\\
34=a_1+30\implies \boxed{4=a_1}$

and now let's use those 2 found folks, to get the 21st term,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=4\\
d=5\\
n=21
\end{cases}
\\\\\\
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zloy xaker [14]

Not sure sorry edit : oh sorry I was suppose to add this in the comment section

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