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GalinKa [24]
3 years ago
11

Two factors of 30 add up to 9. what are they?

Mathematics
2 answers:
Sloan [31]3 years ago
6 0
Well, list out all the factors of 30:
1, 2, 3, 5, 6, 10, 15, 30.
Only 6 and 3 can make 9 alone.
bekas [8.4K]3 years ago
5 0
6 and 3. 6x5=30 and 3x10=30
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0.86÷2 y. 0.91÷7<br><br><br><br>ayudaaaaaaaaaaa(lo escriben en español no hablo ingles)​
beks73 [17]

Answer:

yes get that one 0.78.10

Step-by-step explanation:

3 0
3 years ago
Magnus wants to borrow $26,000 to remodel his kitchen. He is hoping that his monthly payment will be no more than $372. The bank
Oksi-84 [34.3K]

Answer:

About 81 months

Step-by-step explanation:

We'll have to use this formula: A = P x i(1 + i)ˣ / (1 + i)ˣ - 1

A = Montly payment (372)

P = Loan amount (26,000)

i = interest rate/12 (0.043/12 = 0.035833)

x = months (?)

372 = 26,000 x 0.035833(1 + 0.035833)ˣ / (1 + 0.035833)ˣ - 1

First, substitute (1 + 0.035833)ˣ for y just to make things easier

372 = 26,000 x 0.035833y / y - 1

Multiply both sides by y - 1

(y-1)(372 = 26,000 x 0.035833y / y - 1)

372y - 372 = 26,000 x 0.035833y

Divide both sides by y

(372y - 372)/y = (26,000 x 0.035833y)/y

372 - 372/y = 26,000 x 0.035833

Add 372/y to both sides

372 - 372/y = 26,000 x 0.035833

- 372/y              - 372/y

372 = 93.1667 + 372/y

Subtract 93.1667 from both sides

372 = 93.1667 + 372/y

- 93.1667 - 93.1667

372 - 93.1667 = 372/y

Cross multiply

y = 372/(372 - 93.1667)

y = 1.33413

(1 + 0.035833)ˣ = 1.33413

log₁₋₀₀₃₅₈₃₃(1.035833ˣ) = log₁₋₀₀₃₅₈₃₃(1.33413ˣ)

x = 80.59418

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Give a vector parametric equation for the line through the point (−2,−4,0) that is parallel to the line ⟨−2−3t,1−4t,−5t⟩:
eimsori [14]

The tangent vector for the given line is

<em>T</em><em>(t)</em> = d/d<em>t</em> ⟨-2 - 3<em>t</em>, 1 - 4<em>t</em>, -5<em>t</em>⟩ = ⟨-3, -4, -5⟩

On its own, this vector points to a single point in space, (-3, -4, -5).

Multiply this vector by some scalar <em>t</em> to get a whole set of vectors, essentially stretching or contracting the vector ⟨-3, -4, -5⟩. This set is a line through the origin.

Now translate this set of vectors by adding to it the vector ⟨-2, -4, 0⟩, which correspond to the given point.

Then the equation for this new line is simply

<em>L</em><em>(t)</em> = ⟨-3, -4, -5⟩<em>t</em> + ⟨-2, -4, 0⟩ = ⟨-2 - 3<em>t</em>, -4 - 4<em>t</em>, -5<em>t</em>⟩

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3 years ago
Find the equation of the line: parallel to 3x - y = 11 through (-2,0)
aleksandr82 [10.1K]

Answer:

y=3x+6

Step-by-step explanation:

The slope of the line is 3 and the equation will be y=3x+6

5 0
3 years ago
Read 2 more answers
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