See image. I only have an hour. Thank you!

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=2%20%2B%20y%20%3D%201" id="TexFormula1" title="2 + y = 1" alt="2 + y = 1" align="absmiddle" cl

zvonat [6]

Answer: y= -1

Step-by-step explanation:

2+y=1

y=1-2

y=-1

8 0

3 years ago

Read 2 more answers

Solve the SYSTEM: <br> 2x - 3y = 12<br> 3x - 2y = 13

dangina [55]

Answer:

x =69 y= 420

Step-by-step explanation:

69⁹99999999999999999999999999999999999

6 0

2 years ago

If $300 is invested at a rate of 5% per year and is compounded quarterly how much will the investment be worth in 15 years?

dimulka [17.4K]

Answer:

In 15 years the final balance will be $632.15

Step-by-step explanation:

The final balance would be $632.15 and the total compound interest would be $332.15. If you have trouble with these kind of questions in the future I suggest using a compound interest calculator that can be found online :)

5 0

2 years ago

The profit y (in dollars) for a company for selling x games is represented by y=32x. Graph the equation. ANSWER BEFORE 11 FOr BO

natulia [17]

Answer:

I guess that we have the linear equation:

y = 32*x

Where y is the profit, and x is the number of games sold.

Then the first step may be doing a table.

Give x different values, then find the value of y.

if x = 0

y = 32*0 = 0

if x = 1, y = 32*1 = 32

if x = 2, y = 2*32 = 64

Then the points:

(0,0) (1,32) and (2, 64) belong to this line, now we need to conect them with a straigth line and its ready.

The graph will be:

8 0

3 years ago