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3 years ago

Substitute t = 3 and t = 6 to determine if the two expressions are equivalent.

Mathematics

1 answer:

mezya [45]3 years ago

3 0

Answer:

A.The value of both expressions when t=3 is 33.

D.The value of both expressions when t=6 is 51.

E.The two expressions are equivalent.

Step-by-step explanation:

We are given two expressions.

3(2t + 5)

6t + 15

Now let's find the value of these two expressions when t =3 and t = 6

When t =3, the value of the expressions:

3(2*3 + 5) = 3(6 + 5) = 3(11) = 33

6*3 + 15 = 18 + 15 = 33

So the value of both the expressions is 33 when t = 33.

When t = 6, the value of the expressions:

3(2*6 + 5) = 3(12 + 5) = 3(17) = 51

6*6 + 15 = 36 + 15 = 51

The value of both the expressions is 51 when t = 51.

So the following statements are true:

A.The value of both expressions when t=3 is 33.

D.The value of both expressions when t=6 is 51.

E.The two expressions are equivalent.

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Answer:

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The interior angle of a regular polygon is five times its corresponding exterior angle. Find the

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Answer:

Step-by-step explanation:

Regular polygon is one in which each angle and sides is congruent.

Sum of all the exterior angles of any polygon is 360.

Sum of all the interior angles of any polygon is (2n-4)*90

where is n is the no. of sides of polygon.

Let n be the no. of sides of polygon required

Therefore,

Sum of all the interior angles of polygon = (2n-4)*90

since no of sides of polygon is n

therefore, value of each interior angles of the polygon = (2n-4)*90/n (A)

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Given that

The interior angle of a regular polygon is five times its corresponding exterior angle (c)

using the statement A, B and C

(2n-4)*90/n = 5*360/n

1/n is common on both side, hence it gets cancelled.

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