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Dimas [21]
3 years ago
7

Substitute t = 3 and t = 6 to determine if the two expressions are equivalent.

Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

A.The value of both expressions when t=3 is 33.

D.The value of both expressions when t=6 is 51.

E.The two expressions are equivalent.

Step-by-step explanation:

We are given two expressions.

3(2t + 5)

6t + 15

Now let's find the value of these two expressions when t =3 and t = 6

When t =3, the value of the expressions:

3(2*3 + 5) = 3(6 + 5) = 3(11) = 33

6*3 + 15 = 18 + 15 = 33

So the value of both the expressions is 33 when t = 33.

When t = 6, the value of the expressions:

3(2*6 + 5) = 3(12 + 5) = 3(17) = 51

6*6 + 15 = 36 + 15 = 51

The value of both the expressions is 51 when t = 51.

So the following statements are true:

A.The value of both expressions when t=3 is 33.

D.The value of both expressions when t=6 is 51.

E.The two expressions are equivalent.

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A rocket takes off from a height of 30 feet with an initial velocity of 150 ft /sec. The equation that models the path that the
algol13

Answer:

The rocket will hit the floor at 9.57 seconds

Step-by-step explanation:

Given

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