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3 years ago

A bricklayers union charges monthly dues of $3 plus $.18 for each hour worked during

Mathematics

1 answer:

Radda [10]3 years ago

7 0

Answer:

160 hours

Step-by-step explanation:

y=3+.18(hours)

31.80=3+.18(hours)

28.8=.18(hours)

160=hours

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Write your question here keep it simple and clear

igor_vitrenko [27]

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12 + 12 + 18 + 18 = 60

The perimeter is 60 cm

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3 years ago

The center of mass of a triangular solid is at its what?

Leya [2.2K]

I believe it is vertex

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3 years ago

Evaluate 3C1. a)3 b)1 c)2 d)6

murzikaleks [220]

Answer: Option a) 3

Step-by-step explanation:

The formula for calculating combinations is as follows

$nCr = \frac{n!}{r!(n-r)!}$

Where "n" is the amount of items in a set and you can choose "r" from them

3C1 reads as: The combination of 1 in 3. You have a set of 3 elements and choose 1 of them.

$n = 3\\\\r = 1$

So :

$3C1=\frac{3!}{1!(3-1)!}\\\\3C1=\frac{3!}{1!*2!}\\\\3C1=\frac{3*2*1}{1*2*1}\\\\3C1=3$

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3 years ago

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

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3 years ago

12.) When rounding to the nearest 10, what is the largest number that will

Naddika [18.5K]

Answer:

34 is the answer

plz mark brainliest

4 0

3 years ago

Read 2 more answers