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rosijanka [135]
3 years ago
5

Pleas uyall help me pleas ill gibe brainiest

Mathematics
1 answer:
love history [14]3 years ago
8 0
Answer:
A
step by step
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If two zeroes of the polynomial x4-6x3-26x2+138x-35 are x+3 and x-3. Find the other zeroes
ASHA 777 [7]

Answ

Step-by-step explanation:

5 0
3 years ago
You spend $16 on 3 notebooks and x binders . Notebooks cost $2 each and binders cost $5 each. Write an equation you can use to f
Firlakuza [10]

Answer:

Step-by-step explanation:

Write the equation as:

Price of books times number of books + price of binders times number of binders = total price

So then the final answer is 3(2)+5(x)=16

4 0
4 years ago
Is 800 divisible by 5?<br> yes<br> no<br> Submit
Ilia_Sergeevich [38]

Answer: yes(800/5=160)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
Simplify the expression 4 squaere root of 9
nlexa [21]

Answer:

12

Step-by-step explanation:

4 / sqrt {9}

4(3)

4 x 3

12

7 0
2 years ago
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