Answer:
Step-by-step explanation:
d = - 9
a = 4
n = 95
tn = a + (n - 1)*d
t95 = 4 + (94)*(-9)
t95 = 4 -846
t95 = - 842
ar(ΔABO) = ar(ΔCDO)
Explanation:
The image attached below.
Given ABCD is a trapezoid with legs AB and CD.
AB and CD are non-parallel sides between the parallels AD and BC.
In ΔABD and ΔACD,
We know that, triangles lie between the same base and same parallels are equal in area.
⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.
Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)
Now consider ΔABO and ΔCDO,
Subtract ar(ΔAOD) on both sides of (1), we get
ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)
⇒ar(ΔABO) = ar(ΔCDO)
Hence, ar(ΔABO) = ar(ΔCDO).
X=180 and for some reason I need 20 characters so blah
Answer:
Philip, after 12 seconds, is 13.44 meters farther ahead after 12 seconds
Step-by-step explanation:
Philip
6.59 x 12 = 79.08
Mary
5.47 x 12 = 65.64
79.08 - 65.64 = 13.44