1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
balu736 [363]
3 years ago
9

80% of the students in Lea’s class earned an A or a B on the weekly math test. If 20 students got an A or a B, how many students

are in Lea’s class?
Will give Brainliest!!

P.S. This is 6th Grade math on Edge 2020
Here are the options:
0 20 is 80% of what number?
0 20 × 4 = 80, so 100 × 4 = 400 students
0 20 + 60 = 80, so 100 + 60 = 160 students
0 80 ÷ 4 = 20, so 100 ÷ 4 = 25 students
0 80 – 60 = 20, so 100 – 60 = 40 students
Mathematics
2 answers:
frutty [35]3 years ago
5 0
A. 20 is 80 of what number
blondinia [14]3 years ago
5 0

Answer:

25

Step-by-step explanation:

80% got A orB  out of 100% so

20 students are 80% of the class

we need 20% to find all 100% so

80%/4=20% and 20/4=5 students represent 20%

100%= 80%+20% =20students+5students=25 students

You might be interested in
Rafael and his sister bought snacks for movie night.
kolbaska11 [484]

Answer:

Each boxed candies are 5.98, and Each bag of chips are 6.99 Sorry if incorrect

3 0
2 years ago
Read 2 more answers
Which pairs of triangles appear to be congruent? Check all that apply.
Anettt [7]

Answer:

1 3 ...................rotate 3 and it is the same as 1

5 0
3 years ago
I have 8 pennies and some quarters, nickels, and dimes. The number of pennies plus nickels equals the number of dimes. I have 3
GenaCL600 [577]

The answer is D. 10 nickels

3 0
2 years ago
Read 2 more answers
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean (\mu-\sigma,\mu+\sigma)

95% of all values lie within the 1 standard deviation from mean  (\mu-1\sigma,\mu+1\sigma)

99.7% of all values lie within the 1 standard deviation from mean  (\mu-3\sigma,\mu+3\sigma)

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

\mu = 55\\\sigma = 4

68% of all values lie within the 1 standard deviation from mean (\mu-\sigma,\mu+\sigma) = (55-4,55+4)= (51,59)

95% of all values lie within the 2 standard deviation from mean  (\mu-1\sigma,\mu+1\sigma)= (55-2(4),55+2(4))= (47,63)

99.7% of all values lie within the 3 standard deviation from mean  (\mu-3\sigma,\mu+3\sigma)= (55-3(4),55+3(4))= (43,67)

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0
3 years ago
Which of the following expressions represents "no more than 5"?
Ira Lisetskai [31]
Your answer would be x ≤ 5, as ≤ means greater than or equal to
3 0
3 years ago
Read 2 more answers
Other questions:
  • Explain how to compare 0.7 and 5/8.
    5·1 answer
  • What is the measure of angle x?
    8·2 answers
  • Write the equation of a line with slope -4/3 and passes through the y intercept (3,5)
    9·1 answer
  • One three rolls of a single die, you will lose $14 if a 6 turns up at least once, and you will win $6 otherwise. What is the exp
    12·1 answer
  • (x-2) is a factor of x^2-3x^2+kx+14. The value of k is?​
    7·1 answer
  • Write a rule for the function that shifts every point in the plane 10 units down and 4 units to the right
    13·1 answer
  • Perimeter of a square with a side that measures 17.8 ft
    6·1 answer
  • Find the missing exponent. I really need help with this question<br><br> 1/169=(1/13)?<br><br> ? =
    5·1 answer
  • 1/3(9x + 12) = 15<br> a. x=5<br> b. x=3.67<br> c. x=2.8<br> d. x=4.5
    13·2 answers
  • Copy and complete the statement using or =
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!