9514 1404 393
Answer:
(x, y) = (-2, -1) or (2, 1)
Step-by-step explanation:
Substitute for x in the first equation:
(2y)^2 +3(2y)y = 10
10y^2 = 10
y^2 = 1
y = ±1
x = 2y = ±2
Solutions are (x, y) = (-2, -1) or (2, 1).
(x - 3)^2/9 - (y - 2)^2/16 = 1 The vertices of the hyperbola are:
2 answers:
You might be interested in