Question

A ball is thrown with a speed of 100 ft/s in a direction of 30 degrees above the horizontal. determine the horizontal distance in m, the time of flight, and the height to which it rises..Note: you have to label your answer and final answer must be two decimal place​

Answer 1

Answer:

Horizontal distance covered is  270.63ft

Time of flight is 3.125secs

Height to which it rises is 39.06feet

Explanation:

The horizontal distance covered is the range;

Range = U²sin2theta/g

Range = 100²sin2(30)/32

Range = 10000sin60/32

Range = 10000(0.8660)/32

Range = 8660/32

Range = 270.625ft

Hence the  horizontal distance covered is  270.63ft

The time of flight is expressed using the formula;

T = 2Usin theta/g

g is the acceleration due to gravity

T = 2(100)sin30/32

T = 200(0.5)/32

T = 100/32

T = 3.125secs

Hence the time of flight is 3.125secs

Maximum height H = u²sin²theta/2g

H = 100²(sin30)²/2(32)

H = 10000(0.5²)/64

H = 10000(0.25)/64

H = 2500/64

H = 39.0625

Hence the height to which it rises is 39.06feet