Question

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Answer 1

Answer:

130m/s^2 and 1.22s

Explanation:

From V = u+at

Where V, u, a, and t are the final velocity, initial velocity, acceleration and time respectively.

v = 6.75m/s

u = 3.5m/s

t = 0.250secs

a = ?

V = u+at

6.75= 3.5+a(0.250)

6.75-3.5 = 0.250a

3.25=0.250a

Divide both sides by 0.250

3.25/0.250= 0.250a/0.250

a = 130m/s^2

The acceleration of the will be 130 meter per second

Question 2

Speed = distance/time

Given that speed= 4.25m/s

Distance = 5.2m and time = ?

4.25m/s = 5.2m/t

Cross multiply

4.25×t = 5.2

Make t the subject by dividing both sides by 4.25

4.25t/4.25 = 5.2/4.25

t = 1.22s

Hence the time taken will be 1.22 seconds