Answer:
A) J= 398 A/m²
B) E= 1.6×10⁶ N/C
C) P= ×10⁴ W
Explanation:
My work is in the attachment. Comment with questions or if something seems wrong with my work. (Honestly, they seem little high but it could just be the given numbers being unrealistic.) Below I have explanations of each part to match up with the image as well.
Part A:
Current density (J) is defined as the amount of current in a particular cross-sectional area. To get this, we simply need to divide the current (I) by the cross-sectional area of the electron beam tube (A).
Part B:
This one took the most work for me. I used a kinematic equation (yes they apply to electrons) to find the electric field (E). I used a modified form of the familiar: ∆d=V₀τ+aτ²/2
We can use the fact that τ= V/a, a=(qE/m), and V₀=0 here to rewrite the equation in terms of values we know and/or can look up. From there we solve for E and plug in the values.
Part C:
Power (P) is simply work (W) over time (τ). We know what τ is from before and can take W= mV²/2. Plugging these in and reducing some values gives us an equation for power as well.
Answer:
i think the answer it C let me know if i'm wrong
Explanation:
They travel the slowest through gasses
Answer:both the identity and the property of the substance Change
Explanation:both the identity and the property ot the substance Change
Answer:
2:3
Explanation:
Now, Peter and Tom both drove for the same amount of time, t
If Peter only drove 2/5 of the total distance,
Then Distance driven by Tom
= 1-2/5=3/5
Speed= Distance/Time
Let x be the total distance
Peter's Average Speed=2x/5t
Tom's Average Speed=3x/5t
Ratio of Peter's Average Speed to Tom's Average Speed then is:
2x/5t : 3x/5t
Since the denominators are the same, we have
2x:3x
and cancelling out the x on both sides
The ratio of their average speed is 2:3