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Marta_Voda [28]
3 years ago
9

Degreasers can be broken down into two main categories

Engineering
2 answers:
Alex17521 [72]3 years ago
5 0
Degreasers can be categorized to be either water-based or solvent-based.
OLga [1]3 years ago
3 0

<u>Answer:</u>

The degreasers can be broken into two main categories which are wetting the elements and without wetting the elements.

<u>Explanation:</u>

The degreaser which has a wet element for that we need to apply it on one half of the screen and leave it for some minutes. After rinsing it will leave a smooth and shiny sheet. The degreasers without wet are used basically with the direct emulsion for removing dirts by liquid inks or ink cleaners

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Please add comments to your program to explain it. Thank you!
Step2247 [10]

Answer / Explanation:

(1) We should first understand that the input filename are passed in as the first command arguments at command line, respectively.

To do this, we import the data file:

So we have,

import java.io.*;

/**

*  Makes a copy of a file.  The original file and the name of the

*  copy must be given as command-line arguments.  In addition, the

*  first command-line argument can be "-f"; if present, the program

*  will overwrite an existing file; if not, the program will report

*  an error and end if the output file already exists.  The number

*  of bytes that are copied is reported.

*/

public class CopyFile {

  public static void main(String[] args) {

     String sourceName;   // Name of the source file,  

                          //    as specified on the command line.

     String copyName;     // Name of the copy,  

                          //    as specified on the command line.

     InputStream source;  // Stream for reading from the source file.

     OutputStream copy;   // Stream for writing the copy.

     boolean force;  // This is set to true if the "-f" option

                     //    is specified on the command line.

     int byteCount;  // Number of bytes copied from the source file.

     

     /* Get file names from the command line and check for the  

        presence of the -f option.

(2)   If the command line is not one

        of the two possible legal forms, print an error message and  

        end this program. */

   

     if (args.length == 3 && args[0].equalsIgnoreCase("-f")) {

        sourceName = args[1];

        copyName = args[2];

        force = true;

     }

     else if (args.length == 2) {

        sourceName = args[0];

        copyName = args[1];

        force = false;

     }

     else {

        System.out.println(

                "Usage:  java CopyFile <source-file> <copy-name>");

        System.out.println(

                "    or  java CopyFile -f <source-file> <copy-name>");

        return;

     }

     

     /* Create the input stream.  If an error occurs, end the program. */

     

     try {

        source = new FileInputStream(sourceName);

     }

     catch (FileNotFoundException e) {

        System.out.println("Can't find file \"" + sourceName + "\".");

        return;

     }    

     /* If the output file already exists and the -f option was not

        specified, print an error message and end the program. */

   

     File file = new File(copyName);

     if (file.exists() && force == false) {

         System.out.println(

              "Output file exists.  Use the -f option to replace it.");

         return;  

    }      

     /* Create the output stream.  If an error occurs, end the program. */

     try {

        copy = new FileOutputStream(copyName);

     }

     catch (IOException e) {

        System.out.println("Can't open output file \"" + copyName + "\".");

        return;

     }

     

   (3)   /* Copy one byte at a time from the input stream to the output

        stream, ending when the read() method returns -1 (which is  

        the signal that the end of the stream has been reached).  If any  

        error occurs, print an error message.  Also print a message if  

        the file has been copied successfully.  */  

     byteCount = 0;

     

     try {

        while (true) {

           int data = source.read();

           if (data < 0)

              break;

           copy.write(data);

           byteCount++;

        }

        source.close();

        copy.close();

        System.out.println("Successfully copied " + byteCount + " bytes.");

     }

     catch (Exception e) {

        System.out.println("Error occurred while copying.  "

                                  + byteCount + " bytes copied.");

        System.out.println("Error: " + e);

     }    

  }  // end main()  

} // end class CopyFile

8 0
4 years ago
Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and evens (like the 10 or 90)
IrinaVladis [17]

Answer:

#include <iostream>

using namespace std;

int main()

{

int inputNumber ;

cout << "Enter an interstate highway number:";

cin >> inputNumber ;

if(inputNumber<=0 || inputNumber >= 1000)

cout << inputNumber << " is not a valid interstate highway number" << endl ;

else{

if(inputNumber > 99){

cout << "I-"<<inputNumber<< " is auxiliary, ";

int temp = inputNumber % 100 ;

cout <<"serving I-"<<temp<<", ";

if(temp%2==0){

cout << "going east/west." << endl;

}

else{

cout << "going north/south." << endl;

}

}

else{

cout << "I-"<<inputNumber<< " is primary, ";

if(inputNumber%2==0){

cout << "going east/west." << endl;

}

else{

cout << "going north/south." << endl;

}

}

}

return 0;

}

Explanation:

  • Check if input number is greater than 99, then display that the input number is auxiliary.
  • Check if remainder of input number/2 is equal to 0, then display that going east/west.
3 0
3 years ago
Which term refers to the practical applications of scientific knowledge
xz_007 [3.2K]

Answer:

Technology

Explanation:

Technology is defined as the application of scientific knowledge for practical purposes, especially in industry . Sometimes applying scientific knowledge means using less of what we traditionally think of as technology.

7 0
3 years ago
When you see a street with white markings only, what kind of street is it?
Georgia [21]

Answer:

it's a one way street

3 0
4 years ago
The symmetrical load below is connected to a three-phase network. A line current of 25A has been measured. The load resistors ha
boyakko [2]

Answer:

The line voltage of the three phase network is 346.41 V

Explanation:

Star Connected Load

Resistance, R₁ = R₂ = R₃ = 18 Ω

For a star connected load, the line current = the phase current, that is we have

I_L = 25 \, A =  I_{Ph}

Whereby the the voltage across each resistance = V_R is given by the relation;

V_R = I_{Ph} × R

Hence;

V_{Ph} = V_R = I_{Ph} × R  = 25 × 8 = 200 V

Therefore we have;

The line voltage, V_{L} = √3 × V_{Ph} = √3 × 200 = 346.41 V.

Hence, the line voltage of the three phase network = 346.41 V.

3 0
4 years ago
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