Answer:
Manufacturer’s Recommendations means the instructions, procedures, and recommendations which are issued by the manufacturer of any equipment used at the Facility relating to the operation, maintenance, or repair of such equipment, and any revisions or updates thereto from time to time issued by the manufacturer.
Manufacturer’s Recommendations means the instructions, procedures and recommendations which are issued by any manufacturer of the Equipment relating to the operation, maintenance and repair of the Equipment and any revisions to such instructions, procedures and recommendations agreed to by any manufacturer of the Equipment and which are valid at the time such operation, repair and maintenance is being carried out.
Manufacturer’s Recommendations means the written instructions, procedures and recommendations which are issued by the original equipment manufacturer of any plant or equipment used at the Utility Plant relating to the operation, maintenance and repair of such plant or equipment and any revisions thereto issued by the manufacturer, which are valid and applicable at the time such operation, maintenance or repair is undertaken. Notwithstanding the above, Manufacturer’s Recommendations shall not include any instructions, procedures or recommendations of a manufacturer of any plant or equipment that the Owner and the Operator have agreed in writing to exclude from this definition or have agreed in writing should not be followed.
Explanation:
Answer:
The length of tank is found to be 0.6 m or 600 mm
Explanation:
In order to determine the length, we need to find a volume for the tank.
For this purpose, we use ideal gas equation:
PV = nRT
n = no. of moles = m/M
Therefore,
PV = (m/M)(RT)
V = (mRT)/(MP)
where,
V = volume of air = volume of container
m = mass of air = 4.64 kg
R = General Gas Constant = 8.314 J/mol.k
T = temperature of air = 10°C + 273 = 283 K
M = molecular mass of air = 0.02897 kg/mol
P = Pressure of Air = 20 MPa = 20 x 10^6 N/m²
V = (4.64 kg)(8.314 J/mol.k)(283 k)/(0.02897 kg/mol)(20 x 10^6 N/m²)
V = 0.01884 m³
Now, the volume of cylindrical tank is given as:
V = 0.01884 m³ = π(Diameter/2)²(Length)
Length = (0.01884 m³)(4)/π(0.2 m)²
<u>Length = 0.6 m = 600 mm</u>
Malleable and ductile
non metals like plastic also have other properties but can't be malleable and ductile so they r most valuable metallic properties
Answer:
8 mm
Explanation:
Given:
Diameter, D = 800 mm
Pressure, P = 2 N/mm²
Permissible tensile stress, σ = 100 N/mm²
Now,
for the pipes, we have the relation as:
where, t is the thickness
on substituting the respective values, we get
or
t = 8 mm
Hence, the minimum thickness of pipe is 8 mm
