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algol13
2 years ago
11

The design product will be a description of the most efficient thermodynamic cycle required to supply 750 MW of electric power.

Maximum efficiency is achieved by determining the best pressure at which to operate flash evaporator (2, 3, 7, 8) within the limits imposed by the specified parameters.
You should provide:

1. temperature, pressure, and entropy at the state points;

2. overall flow rate of water through the nuclear reactor;

3. heat transfer in the nuclear reactor;

4. % of the overall flow rate passing through the steam turbine;

5. power required for condensate pump 1;

6. power required for condensate pump 2;

7. cooling water flow rate.

Situation: Attached
Diagram: Attached

Water is used as the working fluid of a pressurized-water nuclear power plant (shown in the figure) designed to produce 750 MW of electric power. Saturated liquid exiting the reactor enters a flash evaporator at a selected pressure. The pressure reduction is achieved by a constant enthalpy throttle valve. Thus, a fraction of the water flashes into saturated steam (state 2) and the remainder flows as liquid into the mixing chamber (state 3, p3=p2). The steam enters the turbine,



PLEASE FIND THE SOLUTION WITH CALCULATIONS for 7 parts in total.

Engineering
1 answer:
vlabodo [156]2 years ago
3 0

Answer:

I'm 50s I be sliding on them crabs and we be posting 5 inta a Snapple

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Answer:

4) a) s = +4\,mi, b) \Delta s = 2\,mi, 5) a) s = -2\,mi, b) \Delta s = 10\,mi

Explanation:

4) Let assume that distance with respect to origin is positive at east, while distance is negative at west.

a) The initial displacement is:

s = +4\,mi

b) The distance travelled is:

\Delta s = 2\,mi

\Delta s = 2\,mi

5) a) The final displacement is:

s = -2\,mi

b) The total distance travelled is:

\Delta s = 2\,mi + 6\,mi + 2\,mi

\Delta s = 10\,mi

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true

Explanation:

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Question 2 (Multiple Choice Worth 3 points)
ololo11 [35]

Answer:

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Explanation:

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6 0
3 years ago
A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli
Scrat [10]

Answer:

X_t=2.17391304*10^{-4}

X_r=2.89855072*10^{-4}

e_t=0.0026

e_r=0.0035

Explanation:

From the question we are told that:

Dimension 12*12

Thickness l_t=5mm=5*10^-3

Normal tensile force on top side F_t= 15kN

Normal tensile force on right side  F_r= 20kN

Elastic modulus, E=115Gpap=>115*10^9

Generally the equation for Normal Strain X is mathematically given by

 X=\frac{Force}{Area*E}

Therefore

For Top

 X_t=\frac{Force_t}{Area*E}

Where

 Area=L*B*T

 Area=12*10^{-2}*5*10^{-3}

 Area=6*10^{-4}  

 X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}

 X_t=2.17391304*10^{-4}

For Right sideX_r=\frac{Force_r}{Area*E}

Where

Area=L*B*T

 Area=12*10^{-2}*5*10^{-3}

 Area=6*10^{-4}  

 X_r=2.89855072*10^{-4}

 X_r=2.89855072*10^{-4}

Generally the equation for elongation is mathematically given by

 e=strain *12

For top

 e_t=2.17391304*10^{-4}*12

 e_t=0.0026

For Right

 e_r=2.89855072*10^{-4} *12

 e_r=0.0035

5 0
3 years ago
Hydrogen enters the turbine of an Ericsson cycle at 1040 K, 5 bar with a mass flow rate of 1 kg/s. At the inlet to the compresso
andrew11 [14]

Answer:

a)

Calculate the net power developed by using

the following relation:

Wste=W-W.

Substitute 8728 kw for w, and 2846 kw for w..

Wyle=8728 - 2846

= 5882 kW

Therefore, the net power developed is 5882 kW).

Comment

Step 6 of 7 A

Calculate the thermal efficiency by using the

following relation:

Here, e, is the heat input.

Substitute w, for ..

w

Substitute s882 kw for ws and 8728 kw for w.

5882

1-8728

67.39%

Therefore, the thermal efficiency is 67.39%).

Comments (3)

Step 7 of 7 A

Calculate the back work ratio.

bwr =

Substitute 8728 kw for w, and 2846 kw for w..

bwr - 2846

bwr=8728

=0.326

Therefore, the back work ratio is 10.326).

Explanation:

7 0
3 years ago
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