The design product will be a description of the most efficient thermodynamic cycle required to supply 750 MW of electric power.
Maximum efficiency is achieved by determining the best pressure at which to operate flash evaporator (2, 3, 7, 8) within the limits imposed by the specified parameters.
You should provide:
1. temperature, pressure, and entropy at the state points;
2. overall flow rate of water through the nuclear reactor;
3. heat transfer in the nuclear reactor;
4. % of the overall flow rate passing through the steam turbine;
5. power required for condensate pump 1;
6. power required for condensate pump 2;
7. cooling water flow rate.
Situation: Attached
Diagram: Attached
Water is used as the working fluid of a pressurized-water nuclear power plant (shown in the figure) designed to produce 750 MW of electric power. Saturated liquid exiting the reactor enters a flash evaporator at a selected pressure. The pressure reduction is achieved by a constant enthalpy throttle valve. Thus, a fraction of the water flashes into saturated steam (state 2) and the remainder flows as liquid into the mixing chamber (state 3, p3=p2). The steam enters the turbine,
PLEASE FIND THE SOLUTION WITH CALCULATIONS for 7 parts in total.
You should provide:
1. temperature, pressure, and entropy at the state points;
2. overall flow rate of water through the nuclear reactor;
3. heat transfer in the nuclear reactor;
4. % of the overall flow rate passing through the steam turbine;
5. power required for condensate pump 1;
6. power required for condensate pump 2;
7. cooling water flow rate.
Situation: Attached
Diagram: Attached
Water is used as the working fluid of a pressurized-water nuclear power plant (shown in the figure) designed to produce 750 MW of electric power. Saturated liquid exiting the reactor enters a flash evaporator at a selected pressure. The pressure reduction is achieved by a constant enthalpy throttle valve. Thus, a fraction of the water flashes into saturated steam (state 2) and the remainder flows as liquid into the mixing chamber (state 3, p3=p2). The steam enters the turbine,
PLEASE FIND THE SOLUTION WITH CALCULATIONS for 7 parts in total.
1 answer:
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Answer:
Assumption:
1. The kinetic and potential energy changes are negligible
2. The cylinder is well insulated and thus heat transfer is negligible.
3. The thermal energy stored in the cylinder itself is negligible.
4. The process is stated to be reversible
Analysis:
a. This is reversible adiabatic(i.e isentropic) process and thus
From the refrigerant table A11-A13
sat vapor
m=
b.) We take the content of the cylinder as the sysytem.
This is a closed system since no mass leaves or enters.
Hence, the energy balance for adiabatic closed system can be expressed as:
ΔE
ΔU
)
workdone during the isentropic process
=5.8491(246.82-219.9)
=5.8491(26.91)
=157.3993
=157.4kJ
Answer:
It would take approximately 305 s to go to 99% completion
Explanation:
Given that:
y = 50% = 0.5
n = 1.7
t = 100 s
We need to first find the parameter k from the equation below.
taking the natural logarithm of both sides:
Substituting values:
Also
Substituting values and y = 99% = 0.99
∴ t ≅ 305 s
It would take approximately 305 s to go to 99% completion