The design product will be a description of the most efficient thermodynamic cycle required to supply 750 MW of electric power.
Maximum efficiency is achieved by determining the best pressure at which to operate flash evaporator (2, 3, 7, 8) within the limits imposed by the specified parameters.
You should provide:
1. temperature, pressure, and entropy at the state points;
2. overall flow rate of water through the nuclear reactor;
3. heat transfer in the nuclear reactor;
4. % of the overall flow rate passing through the steam turbine;
5. power required for condensate pump 1;
6. power required for condensate pump 2;
7. cooling water flow rate.
Situation: Attached
Diagram: Attached
Water is used as the working fluid of a pressurized-water nuclear power plant (shown in the figure) designed to produce 750 MW of electric power. Saturated liquid exiting the reactor enters a flash evaporator at a selected pressure. The pressure reduction is achieved by a constant enthalpy throttle valve. Thus, a fraction of the water flashes into saturated steam (state 2) and the remainder flows as liquid into the mixing chamber (state 3, p3=p2). The steam enters the turbine,
PLEASE FIND THE SOLUTION WITH CALCULATIONS for 7 parts in total.
You should provide:
1. temperature, pressure, and entropy at the state points;
2. overall flow rate of water through the nuclear reactor;
3. heat transfer in the nuclear reactor;
4. % of the overall flow rate passing through the steam turbine;
5. power required for condensate pump 1;
6. power required for condensate pump 2;
7. cooling water flow rate.
Situation: Attached
Diagram: Attached
Water is used as the working fluid of a pressurized-water nuclear power plant (shown in the figure) designed to produce 750 MW of electric power. Saturated liquid exiting the reactor enters a flash evaporator at a selected pressure. The pressure reduction is achieved by a constant enthalpy throttle valve. Thus, a fraction of the water flashes into saturated steam (state 2) and the remainder flows as liquid into the mixing chamber (state 3, p3=p2). The steam enters the turbine,
PLEASE FIND THE SOLUTION WITH CALCULATIONS for 7 parts in total.
1 answer:
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Answer:
Explanation:
Using the kinematics equation to determine the velocity of car B.
where;
initial velocity
= constant deceleration
Assuming the constant deceleration is = -12 ft/s^2
Also, the kinematic equation that relates to the distance with the time is:
Then:
The distance traveled by car B in the given time (t) is expressed as:
For car A, the needed time (t) to come to rest is:
Also, the distance traveled by car A in the given time (t) is expressed as:
Relating both velocities:
t = 2.25 s
At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars
i.e.
d + 104.625 = 114.75
d = 114.75 - 104.625
d = 10.125 ft
Answer:
P=361.91 KN
Explanation:
given data:
brackets and head of the screw are made of material with T_fail=120 Mpa
safety factor is F.S=2.5
maximum value of force P=??
<em>solution:</em>
to find the shear stress
T_allow=T_fail/F.S
=120 Mpa/2.5
=48 Mpa
we know that,
V=P
<u>Area for shear head:</u>
A(head)=π×d×t
=π×0.04×0.075
=0.003×πm^2
<u>Area for plate:</u>
A(plate)=π×d×t
=π×0.08×0.03
=0.0024×πm^2
now we have to find shear stress for both head and plate
<u>For head:</u>
T_allow=V/A(head)
48 Mpa=P/0.003×π ..(V=P)
P =48 Mpa×0.003×π
=452.16 KN
<u>For plate:</u>
T_allow=V/A(plate)
48 Mpa=P/0.0024×π ..(V=P)
P =48 Mpa×0.0024×π
=361.91 KN
the boundary load is obtained as the minimum value of force P for all three cases. so the solution is
P=361.91 KN
note:
find the attached pic
