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vodka [1.7K]
3 years ago
9

Jessica baked 3p cookies. Alex baked twice as many cookies as Jessica. Sarah baked 10 fewer cookies than Jessica. Find the total

number of cookies baked in terms of p. A. 2p B. 12p – 10 C. 10 – 12p D. 15 p – 10
Mathematics
1 answer:
makkiz [27]3 years ago
3 0

Answer:

B) 12p - 10

Step-by-step explanation:

J = 3p

A = 2(3p) = 6p

S = 3p - 10

add together:

3p + 6p + 3p - 10 = 12p - 10

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2 x 2 x 2 x 3, so its E

Step-by-step explanation:

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3 years ago
Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ?
skelet666 [1.2K]

Angles formed by the segment \overline{XZ} in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.

  • The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>

Reasons:

The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;

Segment \overline{XZ} is perpendicular to segment \overline{WY}

∠WZX and ∠XZY are right angles by definition of \overline{XZ}  perpendicular to \overline{WY}

∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)

\displaystyle \frac{WZ}{XZ} = \frac{16}{12} = \mathbf{ \frac{4}{3}}

\displaystyle \mathbf{ \frac{XZ}{ZY}}  = \frac{12}{9}  = \frac{4}{3}

Therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9}, which gives, \displaystyle \mathbf{\frac{WZ}{XZ} }= \frac{XZ}{ZY}

Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and

that the included angles between the two sides, ∠WZX and ∠XZY are

congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-

Side, SAS, similarity postulate.

The option that best completes the proof is therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9} which is; <u>16 over 12 equals 12 over 9</u>

Learn more about the SAS similarity postulate here:

brainly.com/question/11923416

4 0
3 years ago
What 5+10<br> 15<br> 12<br> 19<br> 5
Yuliya22 [10]

Answer:

15

just add 10 plus 5

7 0
3 years ago
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A printing company’s costs for printing a book are $500 for labor and running the necessary machinery plus $3 per book printed.
dybincka [34]
C
500+3n
3n
n
Max books = 266 for a total cost of $1298
5 0
3 years ago
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