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3 years ago

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Jessica baked 3p cookies. Alex baked twice as many cookies as Jessica. Sarah baked 10 fewer cookies than Jessica. Find the total

number of cookies baked in terms of p. A. 2p B. 12p – 10 C. 10 – 12p D. 15 p – 10

1 answer:

makkiz [27]3 years ago

3 0

Answer:

B) 12p - 10

Step-by-step explanation:

J = 3p

A = 2(3p) = 6p

S = 3p - 10

add together:

3p + 6p + 3p - 10 = 12p - 10

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Pls help ur girl out with math

Zinaida [17]

135 degrees is your answer

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3 years ago

Water flows from a tank with a rectangular base measuring 80cm by 70cm into another tank with a squarebase of side 60cm. If the

defon

Answer:

70cm

Step-by-step explanation:

,

Since, both of the tank posses the same quantity of water then there volume is the same thing

For rectangular base

Volume= (Lenght × breadth × hheight)

If we substitute values

Lenght= 80 cm

Breadth= 70 cm

height= 45 cm

Volume= 80cm × 70cm × 45cm

Volume= 252000cm^3

For square base

Volume= (side)^2 × height

side =60cm.

But volume of square base= volume of

rectangular base

252000cm^3= 60^2 × height

Height= (252000cm^3)/(60^2 )

Height= 70 cm

Hence, the second tank is 70 cm deep

4 0

3 years ago

Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim

sergejj [24]

Answer:

a) Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

b) $t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958$

c) $p_v =P(t_{34}>2.958)=0.0028$

d) If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.

Step-by-step explanation:

Data given and notation

The sample mean is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=17$ represent the sample mean

$s=4$ represent the sample standard deviation

$n=35$ sample size

$\mu_o =15$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958$

Part c P-value

The degrees of freedom are given by:

$df = n-1= 35-1=34$

Since is a right tailed test the p value would be:

$p_v =P(t_{34}>2.958)=0.0028$

Part d Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.

7 0

3 years ago

How much would $200 invested at 7% interest compounded annually be worth after 5 years? Round your answer to the nearest cent.

e-lub [12.9K]

A= P(1 + r) n (n to the power of)

<span>A= final balance </span>
<span>P= initial quantity </span>
<span>n= number of compounding periods </span>
<span>r= percentage interest rate </span>

<span>P= $200 </span>
<span>n= 9 years </span>
<span>r= 5%= 0.05 </span>

<span>=$200 (1 + 0.05)9 (power of) </span>
<span>=$310.26</span>

7 0

3 years ago

Read 2 more answers

A video club wants to reward its best members with a discount based on the member’s number of movie rentals and the number of ne

ivanzaharov [21]

Answer:

public class MovieRental

{

public static void main(String[] args)

{

Scanner in = new Scanner(System.in);

System.out.print("Enter the number of movie rentals: ");

int movieRentals = in.nextInt();

System.out.print("Enter the number of members referred to the video club: ");

int memberReferral = in.nextInt();

in.close();

double discountVal = Math.min(movieRentals + memberReferral, 75);

System.out.println("The discount is equal to: " + discountVal);

}

}

8 0

3 years ago