Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: mark obtained in an aptitude test by a candidate.
This variable has a mean μ= 128.5 and standard deviation σ= 8.2
You have the data of three scores extracted from the pool of aptitude tests taken.
148, 102, 152
The average is calculated as X[bar]= Σx/n= (148+102+152)/3= 134
An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.
Using the mean and the standard deviation, an outlier is any value that is three standard deviations away from the mean: μ±3σ
Using the population values you can calculate the limits that classify an observed value as outlier:
μ±3σ
128.5±3*8.2
(103.9; 153.1)
This means that any value below 103.9 and above 153.1 can be considered an outlier.
For this example, there is only one outlier, that this the extracted score 102
I hope this helps!
Answer:
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Answer:
Option (2)
Step-by-step explanation:
Given functions are,
c(x) = 
d(x) = x + 3
Equation of the composite function will be,
(cd)(x) = c(x) × d(x)
= 
= 
This function is defined only when denominator is not equal to zero.
(x - 2) ≠ 2
Therefore, for real numbers except x = 2 will be the domain of the composite function.
Option (2) will be the answer.
Solution :
Let y = amount of caffeine at a given time in body.
n = number of hours
So 
ln Y = -0.01 n + C
At n = 0, Y = 130 mg
ln 130 = -0.01 x 0 + C
C = ln 130
When Y = 65
n = 69.315 hours
At n = 24 hours
Y = 102.26 mg
