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Mandarinka [93]
3 years ago
15

A.)$4,000 B.) 5,000 C.)6,000 D.) 7,000 Please only answer if correct

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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PLEASE HELP ME REALLY QUICK
bulgar [2K]

Answer:

41

Step-by-step explanation:

BDA = DBC+CBA

84=5x+3 + 6x-7

Combine like terms

84 = 11x-4

Add 4 to each side

84+4= 11x -4+4

88 =11x

Divide each side by 11

88/11 = 11x/11

8 = x

We want angle  ABC

ABC = 6x-7

       =6*8 -7

      =48-7

     =41

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Kaitlyn saves $6 each week. After correctly carrying out the Solve step of the five-step problem-solving plan, which solution sh
ch4aika [34]

Answer:

1. 10 weeks

Step-by-step explanation:

Apparently, we want to find the number of weeks (w) that Kaitlyn must save $6 in order to have a total of $60.

... $6 × w = $60

Divide by $6 to get ...

... w = $60/$6 = 10

Kaitlyn must save for 10 weeks (if she starts with a balance of 0).

_____

<em>Comment on the problem statement</em>

The problem reads like we came in somewhere in the middle of it. We don't know what other steps you've been asked to perform, or any of the details of the problem you're asked to solve. We don't have Kaitllyn's initial balance, for example, which is essential to determining how long she must save. (If Kaitlyn's initial balance is $33, for example, she must only save for 4.5 weeks.)

7 0
3 years ago
Grant pays 10 cents per minute plus $5 per month for telephone long distance. Write an algebraic expression for m minutes of lon
dolphi86 [110]
The question is asking for the amount of minutes Grant can possibly use in a month. So to <span>algebraically express this, the equation, </span>0.10 m+5=$ sums it up.
5 0
3 years ago
What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

7 0
3 years ago
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