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galina1969 [7]
3 years ago
5

Hey besties can y'all help me out

Chemistry
1 answer:
Lostsunrise [7]3 years ago
5 0

you need to <u>lose one electron </u>

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What will happen if there is an insufficient supply of oxygen during the combustion of a hydrocarbon?
Kamila [148]
As long as there is some oxygen, the reaction will occur. If there is an insufficient amount of oxygen, then the oxygen will be the limiting reacting and there will be excess of the other reactants. 
8 0
4 years ago
9. How many grams of zinc are needed to produce 12 grams of zinc chloride according to the following equation? Y-
tensa zangetsu [6.8K]

Given :

A balanced chemical equation :

Zn +Cl_2->ZnCl_2

To Find :

How many grams of zinc are needed to produce 12 grams of zinc chloride.

Solution :

Moles of ZnCl_2 ,

n=\dfrac{Given \ wt}{Molecular\ Mass}\\\\n =\dfrac{12}{136.30}\ mol\\\\n=0.088\ mol

Now, by balanced chemical equation we can say that 1 mol of Zn produce

1 mol of ZnCl_2 .

So, 0.088 mol of Zn is required to produced 0.088 mol of ZnCl_2 .

Mass \ required = molecular \ mass \times moles\\\\m = 65.38 \times 0.088\\\\m=5.8 \ gm

Therefore, 5.8 grams of zinc is required.

Hence, this is the required solution.

4 0
3 years ago
Answer to AP chem question
andrew11 [14]

Answer:

See the answer and explanation below, please.

Explanation:

The formulas and names of the compunds are:

Na3 P04 (Sodium Phosphate )-->The phosphate suffix corresponds to the highest number of phosphorus oxidation (+5)

Zn PO4 (Zinc Sulfate)-->The phosphate suffix corresponds to the highest number of phosphorus oxidation (+5)

KN03 ( Potassium Nitrate)-->The nitratete suffix corresponds to the highest number of nytrogen oxidation (+5)

Fe 2 (C03)3 (Iron (III) Carbonate / Dihydrous Trioxide / Ferric Carbonate)-->The carbonate suffix corresponds to the highest number of carbon oxidation (+4)

Pb (Co2)2 (Lead carbonate (IV) / Lead trioxocarbonate (IV)))-->The carbonate suffix corresponds to the highest number of carbon oxidation (+4)

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3 years ago
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4 0
3 years ago
What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams of hydrogen peroxide, H2O2?
daser333 [38]

Answer:

6 mol/L

Explanation:

You should know or have the equation to solve for Molarity which is;

M = n/v          (M: Molarity) (n: moles of solute) (v: Liters of solute)

You can start off differently but I would start by converting the mL to L. This is your "v" value.

50.0 mL/ 1000 mL = <em>0.05 L</em>

Now, you have to convert grams to moles in order to solve for molarity (M).

1.) On the periodic table find the molecular weights of H and O.

H= 1.01 g/mol         O= 16.00 g/mol

2.) Multiply them and then add them together to have their combined molecular weights. (You have to multiply by 2 because of their equation; H2O2).

2(1.01) + 2(16.00)= 34.02 g/mol

3.) Now, you're going to use the "picket fence method" or whichever your teacher taught you to convert from grams to moles. This will be your "n" value. (I cannot show it on here without it looking weird, so my sincere apologies.)

10.0 g/ 34.02 g = <em>0.2939 mol</em>

<em />

4.)You are now going to plug in your answers into the equation for Molarity.

M= 0.2939 mol / 0.05 L = <em>5.878 mol/L</em>

5.) I am sure your professor might be a stickler so for sig figs sake when you multiply or divide use the smallest amount of sig figs you see which is 1. Round 5.878 to 6 mol/L

Sorry this explanation is very long let me know if you need a better more written out explanation.

4 0
4 years ago
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