ANSWER: VIRTUAL TEAM
EXPLANATION:
A VIRTUAL TEAM is also referred to as distributed team or geographically dispersed team, or remote team.
A VIRTUAL TEAM refers to a group of personnel or individuals who work together from varrying or different geographic locations and rely/linked by information and communication technologies.
Examples of incorporated information and communication technologies include email, FAX, and video or voice conferencing services (e.g Skype).
The main reason of this link is to enhance collaborative efforts of the individuals involved towards achieving a particular goal or task.
However, two types of virtual team had been described, which are Global Virtual Team and Local Virtual Team.
Global Virtual Team are located in different countries/cities all over the world. This team may comprise employees of different companies, joining their efforts and resources, towards a shared project and achieving a common goal.
Whereas, members of Local Virtual Team usually belong to the same company, which is either big or small, having adequate resources (information and communication technologies) to establish and maintain virtual team workplaces. Hence, enhancing its employees into a productive remote group.
Answer:
It could affect the way we face certain problems. It can also affect the way we perceive different problems.
Explanation:
The answer that best fits the blank is the term SYNERGISTIC. Synergistic process refers to the relationship between a stressful event and coping. This means that both of these factors relate or interact in order to produce a greater effect or impact.
Answer:
A) 2.02 standard deviations from 600 - a win
B) The last interval was a close call.
Explanation:
n = 2300
p = 0.47, q = 1-p = 0.53
μ = np = 1081
σ = √(npq) = 23.94
Z.025 = 1.96
B) Finding both confidence interval:
Confidence Interval = (μ-1.96(23.94)/√2300, μ+1.96(23.94)/√2300)
= (1081 - 0.978, 1081 + 0.978)
= (1080.022, 1081.978)
(1080-600)/23.94 = 2.02 standard deviations from 600 - a win
B)
AS above
n=450, p=.54, q=.46
μ=np=243, σ=√(npq)=10.6
confidence interval (243-1.96(10.6)/√450 , 243+1.96(10.6)/√450)
= 243-.98, 243+.98) = (242.0, 243.98)
(244-225)/10.6=1.8 standard deviations from win
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