Question

8.0 mol of methane gas reacts completely in a 2.00L container containing excess O2 in 3.2s. Find average rate of consumption of methane

Answer 1

Answer:

1.3 M/s

Explanation:

Step 1: Given data

• Initial amount of methane (ni): 8.0 mol

• Final amount of methane (nf): 0 mol (it reacts completely)

• Volume of the container (V): 2.00 L

• Time elapsed (t): 3.2 s

Step 2: Calculate the average rate of consumption of methane

Methane burns in excess oxygen according to the following equation.}

CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O

We can calculate the average rate of consumption of methane (r) using the following expression.

r = - Δn/V × t = - (nf- ni) / V × t

r = - (0 mol - 8.0 mol) / 2.00 L × 3.2 s = 1.3 M/s