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Alborosie
2 years ago
8

Golgi body function

Chemistry
1 answer:
olasank [31]2 years ago
5 0

Explanation:

GOLGI BODY - transportation of lipids and steroids.

LYSOSOME - destruction of malfunctioning or worn out cell organelles.

MITOCHONDRIA - oxides glucose to give energy to the cell in a form of cellular respiration.

VACUOLE - FOOD VACUOLE for storage of food while WATER VACUOLE eliminates excess water by a process called OSMOREGULATION.

CELL WALL - provides rigidity for the plant cell.

CHLOROPLAST - pigmented organelle of the plant which functions to manufacture food by a phenomenon known as PHOTOSYNTHESIS.

RIBOSOME - synthesizes protein and enzymes.

ENDOPLASMIC RETICULUM - The ROUGH ENDOPLASMIC RETICULUM has RIBOSOMES attached to it while the SMOOTH ENDOPLASMIC RETICULUM has nothing attached, they transport proteins and enzymes

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Elden [556K]
The following are neutral salts: NANO3, BaBr2 AND Ba[OH]2. 
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3 years ago
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At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5
Annette [7]

Answer:

4600s

Explanation:

2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

-\frac{d[B]}{dt}=k[B] - - -  -\frac{d[B]}{[B]}=k*dt

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.  

-\frac{d[P(B)]}{P(B)}=k*dt  

-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt

Integrating we get:

\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt

-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})

Clearing for t2:

\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}

ln[P(N_{2}O_{5})]=ln(650)=6.4769

ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333

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3 years ago
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Answer:

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PV = nRT

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what we have are;

n = 1 mole

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But this is not what we want to calculate

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