Question

How many moles of PbCl2 are produced if 14 moles of AIC13 are consumed?

Answer 1

Answer:

14 moles AlCl3 x 3 moles PbCl2/2 moles AlCl3 = 21 moles of Pb(NO3)2

Explanation:

Using dimensional analysis and the mole ratios from the balanced equation, we can calculate moles of PbCl2/2 formed from 14 moles of AlCl3...

I hope this helps and if I am wrong I am sorry but i am positive that your answer.

Answer 2

Answer:

21 moles of PbCl2 are produced

Explanation:

In order to produce PbCl2 from AlCl3 some reaction is needed. Assuming all the chlorine in the reactants is present in the AlCl3 and all the chlorine in the products is present in the PbCl2, then:

Pb compound + 2 AlCl3 -> 3 PbCl2 + Al compound

The aforementioned chlorine assumption is needed to find the stoichiometric coefficients of the balanced equation. So, for every 2 moles of AlCl3 that react, 3 moles of PbCl2 are formed, then for 14 moles of AlCl3:

2 moles of AlCl3/14 moles of AlCl3 = 3 moles of PbCl2/x moles of PbCl2

x = 3*14/2

x = 21 moles of PbCl2 formed