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3 years ago

Slove the equation -3x+1+10x=x+4

Mathematics

2 answers:

arlik [135]3 years ago

6 0

Answer:

Step-by-step explanation:

kakasveta [241]3 years ago

3 0

Answer:

$x=2$

Step-by-step explanation:

$-3x+1+10x=x+4$

$-3x+10x-x=4-1$

$6x=3$

$x=2$

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X + 3 = y,

Anna007 [38]

3. X= y-3

You subtract 3 to the other side to make X the subject of the formula.

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What is 3.01 the one repeating what is it as a mixed number

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The answer: 3 1/100

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3 years ago

Find the equation of a line that is perpendicular to line g that contains (P, Q). coordinate plane with line g that passes throu

maw [93]

Answer:

$y - Q = - \frac{1}{4}(x - P)$

Step-by-step explanation:

Line g passes through (-2,6) and (-3,2).

The slope of line g is given by:

$\frac{ y_2-y_1}{x_2-x_1}$

Let's substitute the values to get:

$\frac{2 - 6}{ - 3 - - 2}= \frac{ - 4}{ - 1} = 4$

The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.

i.e -1/4

If this line passes through (P,Q), then the equation is:

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7 0

3 years ago

Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)

Likurg_2 [28]

Answer:

$d = 14$

$(-2,-1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

(5, -1)

(-9, -1)

Step 2: Find distance d

Substitute: $d = \sqrt{(-9-5)^2+(-1-(-1))^2}$
Simplify: $d = \sqrt{(-9-5)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-14)^2+(0)^2}$
Evaluate: $d = \sqrt{196}$
Evaluate: $d = \14$

Step 3: Find Midpoint

Substitute: $(\frac{5-9}{2},\frac{-1-1}{2})$
Subtract: $(\frac{-4}{2},\frac{-2}{2})$
Divide: $(-2,-1)$

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3 years ago

Analyze the diagram below and complete the instructions that follow.

Kamila [148]

I think the ans is 10

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3 years ago