Answer:
14.336 g MnF₂
Explanation:
number of moles = mass / molecular weight
number of moles of MnI₂ = 55 / 309 = 0.178 moles
number of moles of F₂ = 55 / 38 = 1.447 moles
From the reaction and the number of moles calculated we deduce that the fluorine F₂ is a limiting reactant.
So:
if 13 moles of F₂ reacts to produce 2 moles of MnF₃
then 1.447 moles of F₂ reacts to produce X moles of MnF₃
X = (1.447 × 2) / 13 = 0.223 moles of MnF₃ (100% yield)
For 57.2% yield we have:
number of moles of MnF₃ = (57.2 / 100) × 0.223 = 0.128 moles
mass = number of moles × molecular weight
mass of MnF₃ = 0.128 × 112 = 14.336 g
Oxygen has 8 protons and 10 electrons due to the addition of 2 electrons, determined from the ion charge. Likewise an ion of potassium has 19 protons and 18 electrons. Charge on fluorine would be -1 and charge on calcium would be +2. Atomic number is the same as the number of protons, so it would be 6, the mass number is the sum of protons and neutrons which would be 13, and the charge is 0, as it is an atom and not an ion.
The postulates of Dalton's theory were:
1) Elements are made of extremely small particles called atoms
2) <span>Atoms of a given element are identical in size, mass, and other properties
</span>3) <span>Atoms cannot be subdivided, created, or destroyed</span>
4) Atoms combine in whole number ratio to form compounds
5) Chemical reactions are the rearrangement of atoms
The third postulate has been disproved by modern science, in which the atom has been split and been subdivided into smaller parts such as the neutron, proton and electron, which are further subdivided into quarks, gluons, and kaons.
The second postulate was also disproved upon the discovery of isotopes.
Closer=Burn
Farther=Freeze
We are the perfect distance away from the sun for it to sustain life.
Answer:
1640 kJ are involved in the reaction
Explanation:
In the reaction:
B₂H₆(g) + 6Cl₂(g) → 2 BCl₃(g) + 6HCl(g)
<em>1 mol of B₂H₆(g) with 6 moles of Cl₂(g) produce 1396 kJ of energy.</em>
<em />
Now if 32.5g of B₂H₆(g) react with excess Cl₂(g), moles involved in reaction are:
If 1 mol produce 1396kJ of energy, 1.175 moles produce:
Thus, <em>1640 kJ are involved in the reaction</em>
