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Delicious77 [7]
4 years ago
14

triangle has sides measuring , , and units. What are the angle measures of the triangle? A. 30°, 60°, 90° B. 45°, 45°, 90° C. 60

°, 60°, 60° D. 30°, 52°, 60°
Mathematics
2 answers:
Mariulka [41]4 years ago
8 0
I think that the correct answer is A
levacccp [35]4 years ago
3 0
I saw your question and the attachment

Answer is A

Hope it helps!
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Name the adjacent angles in the following diagram
svlad2 [7]
<span>adjacent angles

m<BAC and m<CAD

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7 0
3 years ago
Given the formula,v= 4.5 + at,find the value of v when a=1.6 and t=3.5.​
jarptica [38.1K]

Answer:

v=10.1

Step-by-step explanation:

v= 4.5 + at  -------> equation 1

given

a=1.6

t=3.5

so we will plug in the value in equation 1

v = 4.5 + (1.6 x 3.5)

v = 4.5 + 5.6

v = 10.1

7 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
The horizontal change between 2 points
Mamont248 [21]

Answer:

slope is the ratio of the vertical and horizontal changes between two points on a surface or a line. The vertical change between two points is called the rise, and the horizontal change is called the run.

Step-by-step explanation:

To know the horizontal change between two points you need to know the two points.

7 0
3 years ago
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Please help will give brainliest
natulia [17]

Answer:

A) it wouldn't fit

Step-by-step explanation:

7 0
3 years ago
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