Which street is parallel to 2nd St? A. 1st St. B. 3rd St. C. 4th St.
2 answers:
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Answer:
Equations:
--- Cindy
--- Ruben
Solution to equation:
Time they have the same amount: 14 minutes
Number of cards they have at that time: 140 flashcards
Step-by-step explanation:
Solving (a): Variables and what they represent
The variables to use are x and y
Where x represent the minutes and y represents the number of flashcards in x minutes
Solving (b): System of linear equation
Cindy:
per minute
Total number of flashcards (y) in x minutes is:
Ruben:
per minute
Total number of flashcards (y) in x minutes is:
Solution to Equations:
Time they have the same amount.
To do this, we
expressions
i.e.
Collect Like Terms
Number of cards they have at that time.
Here, we simply substitute 14 for x in any of the equations.
or
Your distance(d) is 1,814.4
1814.4 m = 5.6t square
then you square root 5.6t
the square root eliminates the square
you square root 1,814.4 m
(I rounded 42.6) then divide 42.6 by 5.6
(I rounded 7.6)
1814.4 m = 5.6t square
then you square root 5.6t
the square root eliminates the square
you square root 1,814.4 m
(I rounded 42.6) then divide 42.6 by 5.6
(I rounded 7.6)