Answer:
x = 6
Step-by-step explanation:
Answer:
Step-by-step explanation:
We need to find the conditional probability P( T1 < s|N(t)=1 ) for all s ≥ 0
P( time of the first person's arrival < s till time t exactly 1 person has arrived )
= P( time of the first person's arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
{ As till time t, we know that exactly 1 person has arrived, thus relevant values of s : 0 < s < t }
P( time of the first person arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
= P( exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
P(exactly x person has arrived till time t ) ~ Poisson(kt) where k = lambda
Therefore,
P(exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
= [ kse-ks/1! ] / [ kte-kt/1! ]
= (s/t)e-k(s-t)
Answer:
x = negative 9/4
Step-by-step explanation:
-2x-11=6x+7
-2x-11+11=6x+7+11
-2x=6x+18
-2x-6x=6x+18-6x
-8x=18
Answer: 37
Step-by-step explanation:
Answer:
23
Step-by-step explanation:
Given Shane hits 5 HRs out of 100 At-bats,
