Use a system of equations.
(x=# of small dogs, y=# of big dogs)
x+y=9 (times by -5) -5x-5y=-45
5x+8y=51
Then add the equations together and the x's cancel.
3y=6
y=2
So he walked 2 big dogs and 7 little dogs.
Seems like a wordplay question.
A "scale" is used for measuring length.
A different sort of "scale" is used for measuring mass.
Answer: 3x + 13 = 8
Step-by-step explanation: If u multiply the number by 3 and add 13, the answer would be 8
If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs,
Therefore the total number of legs will be 4x + 2y which is equal to 36 .
Therefore, we have two equations
x + y = 14
4x + 2y = 36 solving them simultaneously using elimination
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
2x = 8 ( subtracting the equations)
x = 4
y = 14 -(4)
= 10
Therefore, there are 4 zebras and 10 peacocks in the zoo
Answer:
r = 9 that's your answer.
Hope it's correct, appreciate if you could let me know
Step-by-step explanation:
