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zheka24 [161]
3 years ago
12

How much excess reactant remains from the reaction of 8.3g of sodium and 4.5g of chlorine?

Chemistry
2 answers:
just olya [345]3 years ago
5 0
Answer: I wanna say A but I’m not 100% sure
But I hope this helps at least a little :)
algol [13]3 years ago
3 0

Answer:

5.4 g Na

Explanation:

Calculate the mass of sodium chloride from both reactants. The lesser value is the amount is the theoretical yield. Subtract the mass of the calculated mass of sodium chloride from the mass of the reactants.

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katrin2010 [14]
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3 0
3 years ago
Calculate the mass of a liquid with a density of 2.3 g/mL and a volume of 30 mL.
san4es73 [151]

Hello there!

First you had to multiply by the density by the volume since D=M/V. Please make sure when your units has the same thing and it should be cancel it out.

2.3g/mL*30 mL= 69L is the right answer.

Hope this helps!

Thank you for posting your question at hereon Brainly.

-Charlie

5 0
4 years ago
M<br> + e -&gt; M-1<br> This reaction represents
arlik [135]

Answer:

Reduction.

Explanation:

Reduction is the gain of electron.

8 0
4 years ago
A solution contains 2.2 × 10-3 M in Cu2+ and 0.33 M in LiCN. If the Kf for Cu(CN)42- is 1.0 × 1025, how much copper ion remains
Taya2010 [7]

Answer:

[Cu²⁺] = 2.01x10⁻²⁶

Explanation:

The equilibrium of Cu(CN)₄²⁻ is:

Cu²⁺ + 4CN⁻ ⇄ Cu(CN)₄²⁻

And Kf is defined as:

Kf = 1.0x10²⁵ = [Cu(CN)₄²⁻] / [Cu²⁺] [CN⁻]⁴

As Kf is too high you can assume all Cu²⁺ is converted in Cu(CN)₄²⁻ -Cu²⁺ is limiting reactant-, the new concentrations will be:

[Cu²⁺] = 0

[CN⁻] = 0.33M - 4×2.2x10⁻³ = 0.3212M

[Cu(CN)₄²⁻] = 2.2x10⁻³

Some [Cu²⁺] will be formed and equilibrium concentrations will be:

[Cu²⁺] = X

[CN⁻] = 0.3212M + 4X

[Cu(CN)₄²⁻] = 2.2x10⁻³ - X

<em>Where X is reaction coordinate</em>

<em />

Replacing in Kf equation:

1.0x10²⁵ = [2.2x10⁻³ - X] / [X] [0.3212M +4X]⁴

1.0x10²⁵ = [2.2x10⁻³ - X] / 0.0104858X + 0.524288 X² + 9.8304 X³ + 81.92 X⁴ + 256 X⁵

1.04858x10²³X + 5.24288x10²⁴ X² + 9.8304x10²⁵ X³ + 8.192x10²⁶ X⁴ + 2.56x10²⁷ X⁵ = 2.2x10⁻³ - X

1.04858x10²³X + 5.24288x10²⁴ X² + 9.8304x10²⁵ X³ + 8.192x10²⁶ X⁴ + 2.56x10²⁷ X⁵ - 2.2x10⁻³ = 0

Solving for X:

X = 2.01x10⁻²⁶

As

[Cu²⁺] = X

<h3>[Cu²⁺] = 2.01x10⁻²⁶</h3>

5 0
3 years ago
The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.
Rzqust [24]

Answer:

Order of the cycle:

Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.

Explanation:

<u>Step -1:</u>

Carbon dioxide is taken in by plants during photosynthesis.

<u>Step -4;</u>

The animal eats a plant and uses its carbohydrates for energy.

<u>Step - 3</u>

The animal releases the carbon dioxide back into the atmosphere during respiration.

<u>Step -2</u>

The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.

Therefore, order of the cycle is Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.

5 0
3 years ago
Read 2 more answers
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