Calculate the change in energy of an atom that emits a photon of wavelength 2.21 meters. (Planck’s constant is 6.626 x 10-34 jou le seconds, the speed of light is 2.998 x 108 m/s)
1 answer:
The Energy of an atom that emits a photon of wavelength 2.21 m is
3.028 × 10⁻¹⁹ J. I attached the working and the answer to the question below. I hope I was able to help.
Please note that C = speed of light, ν = frequency, λ= wavelength, h = Planck's Constant
You might be interested in
Answer:
See explaination
Explanation:
See attachment for the drawing of the intermediate products b and c (both are neutral; omit byproducts).
Answer:
The solution to this question can be defined as follows:
Explanation:
The complete question is defined in the attached file.
Here:
Answer:
Stronger!
Explanation:
The <u>stronger</u> the forces among the particles in a sample of matter, the more rigid the matter will be.
Answer:
TRUE
Explanation:
Standard temperature is 273K and 350°C is 623K.
V/V' = T/T'
3/6.84 = 273/T'
T' = (273×6.84)/3
=> T' = 623K
So it is true.
Answer:
Nobody. This really isn't the place to be looking for a date. Ill take the points though.
