Answer:
A) The value of a is <u>29</u>.
B) The value of b is <u>greater than 29</u>.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,

We have to solve for a.

By using addition property of equality, we will add both side by 9;

Hence the value of a is <u>29</u>.
Solving for Part B.
Given,

We have to solve for b.

By using addition property of inequality, we will add both side by 9;

Hence the value of b is <u>greater than 29</u>.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
4096 ways : 8 candy toppings plus 4 fruit toppings is 12. Then 2^12 (2 different types of toppings and the 12 of total toppings) = 4096
Answer:
1850
Step-by-step explanation:
The problem is asking you how many kids (predicted by the superintendent) will buy lunches for 1-2 days. Since you know the percentage predicted and the student amount, just multiply as a decimal (convert by putting the number over 100 as a fraction.)
5000*0.37=1850
Answer:
Question 1: y-11x+5 I think; Question 2: I'm not sure
Step-by-step explanation:
-14/15+-2v/3+v/3 that is the answer