Prove that: log b (p2 - q2) – log b (p + q) = log b (p – q)

Mathematics

1 answer:

viva [34]3 years ago

3 0

Answer:

Step-by-step explanation:

The formulas used to solve :

$[ log_b(\frac{x}{y}) = log_bx - log_by]$

$(p^2 - q^2) = (p+q)(p-q)$

$log_b(p^2 - q^2) - log _b(p + q) = log_b(p-q)\\\\log_b(\frac{(p^2 -q^2)}{(p+q)}) = log_b(p-q)\\\\log_b(\frac{(p+q)(p-q)}{(p+q)}) = log_b(p-q)\\\\log_b(p-q) = log_b(p-q)\\\\$

Hence proved.

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kirill [66]

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