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Andru [333]
3 years ago
14

The graph below represents the price of sending text messages using the services of a phone company. What is the constant of pro

portionality? A. 12 B. 24 C. 46. D. 48

Mathematics
1 answer:
anastassius [24]3 years ago
5 0
Ah, direct variation/proportion.
That is simply a linear equation with a y-intercept of 0.
So... let's solve this.
Simply put, a direct variation multiplies the x-value by a constant to get the y-value.
Let's take the point (2, 48) on this graph and solve for the constant of proportionality:
2a=48
We easily solve that and get our answer of a=24. (B)

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Step-by-step explanation:

Mean (Average):

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6 0
3 years ago
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Jernel has to figure out the area of her square garage. she knows that one side of the garage is equal to the length of her rabb
Readme [11.4K]

Answer: 100 square units.

Step-by-step explanation:

Given: Jernel has to figure out the area of her square garage.

She knows that one side of the garage is equal to the length of her rabbit pen.

Now, the length of the rabbit pen = 10 units

Then , the length of the garage will be 10 units

Now, Area of square = \text{(side)}^2=10^2=100\text{units}^2

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4 0
3 years ago
LCM of x<sup>2</sup>+5x+6 and x<sup>2</sup>-x-6 is ………………………
sergejj [24]

Answer:

(x^2 - 9)(x + 2)

Step-by-step explanation:

Given:

x^2 + 5x + 6

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Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

x^2 + 5x + 6

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(x^2 + 3x) + (2x + 6)

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x^2 - x - 6

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(x + 2)(x - 3)

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

x^2 + 5x + 6 = (x + 2)(x + 3)

x^2 - x - 6 = (x + 2)(x - 3)

The common factors would be: =>

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(x - 3)

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4 0
3 years ago
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Sever21 [200]

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-1 3/8

Step-by-step explanation:

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Ten less than 3 times a number is the same as that number increased by 4
Olenka [21]
3x - 10 = x + 4 <== ur equation

three times a number.....3x...with the x representing the number
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is the same as...means =
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3x - 10 = x + 4
3x - x = 4 + 10
2x = 14
x = 14/2
x = 7....and that number is 7
3 0
3 years ago
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