It is not possible. Since one of the angles has to be a right angle, the other two angles would have to add to 90. Therefore, neither of these angles can be more than 90 degrees.
Hope this helps
Answer:
2(x + 4) / 6(x² - 3x - 28)
Step-by-step explanation:
Area of a rectangle = length × width
Length = 2/(x² - 3x - 28)
Width = x² - 16/6x - 24
= (x + 4)(x - 4) / 6(x - 4)
= (x + 4) / 6
Area of a rectangle = length × width
= 2/(x² - 3x - 28) × (x + 4) / 6
= 2(x + 4) / (x² - 3x - 28)6
= 2(x + 4) / 6x² - 18x - 168
= 2(x + 4) / 6(x² - 3x - 28)
Area of a rectangle =
2(x + 4) / 6(x² - 3x - 28)
Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.
