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natulia [17]
4 years ago
11

3. Paula commutes 60 km each day for work, five days a week, nine months of the year. She travels 720

Mathematics
1 answer:
bezimeni [28]4 years ago
7 0

Answer:

16,080 km.

Step-by-step explanation:

We want the total number of kilometers in one year.

so

4 weeks /month.

for Work:   9 months in the year  60 km/day  5 days/week

Family Visit :  720 km for 4 times a year

Personal:  200 km / month

Work total = 60 km/day * 5 days/week * 4week/month * 9 months

WorkTotal= 60*5*4*9 = 10,800 km

FamilyTotal= 4*720 = 2880 km

Personal = 200*12 = 2400 km

Total = 10,800 + 2880 + 2400 = 16,080 km

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1. Marlene is going on a camping trip with a group of friends. She brings 3 boxes of granola bars,
andrey2020 [161]

Answer:

13.5

Step-by-step explanation:

total boxes of granola is = 3 + 2 + 1

                                         =  6 boxes

6 boxes = 57 bars

1 box  =  57 / 6

1 box  = 9.5 + 3

           = 13.5 (ANS)

i hope my ans is correct if not i apologise.

3 0
2 years ago
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Daniel puts some wheat flour into an empty bowl. Then he add 2/3 cup rye flour to make a total of 2 5/12 cups of flour. How much
lozanna [386]

Answer:

1 3/4 cups of wheat flour is in the bowl

Step-by-step explanation:

x + 2/3 = 2 5/12

First, convert the 2/3 to 12ths by multiplying numerator and denominator by 4 = 8/12

Then convert the 2 5/12 to an improper fraction 29/12

x + 8/12 = 29/12

subtract 8/12 from both sides

x = 21/12 = 1 9/12 = 1 3/4

6 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Please help???? Geometry
Musya8 [376]
Any line can be expresses as:

y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)

First find the slope:

m=(2-0)/(8-0)=2/8=1/4 so we have thus far:

y=0.25x+b, we solve for b using any point on the line, (8,2)

2=0.25(8)+b

2=2+b 

0=b

So the line is:

y=.25x  which they might also express as y=x/4

The answer is E. (1/4)x


6 0
3 years ago
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What is 9-3y=x I don't know this one
torisob [31]
The answer is 
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1- Subtract 9 from both sides.
-3y = x - 9
2- Divide both sides by -3
y = - x-9/3
4 0
3 years ago
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