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Stells [14]
2 years ago
15

Plz help urgent 20 PTS

Mathematics
2 answers:
Scilla [17]2 years ago
8 0

Answer:

ABFE - 50

BFGC - 25

EFGH - 50

Step-by-step explanation:

LenKa [72]2 years ago
4 0

Answer:

abfe 50. bfgc 25 efgh 50

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If a polynomial function f(x) has roots 3 and square root of 7, what must also be a root of f(x)
Neko [114]

Answer:

x = - \sqrt{7}

Step-by-step explanation:

Radical roots occur in pairs, that is

x = \sqrt{7} is a root then so is x = - \sqrt{7}

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3 years ago
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What is B^y=x in logarithmic form?
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Answer:

The logarithmic function for x = 2y is written as y = log2 x or f(x) = log2 x. The number 2 is still called the base. In general, y = logb x is read, “y equals log to the base b of x,” or more simply, “y equals log base b of x.” As with exponential functions, b > 0 and b ≠ 1

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2 years ago
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Find the slope of the line that passes through
Crazy boy [7]
Slope: (y2-y1)/(x2-x1)
(-3+5)/(-1-7) = 2/-8 = -1/4
The answer is d) -1/4
3 0
3 years ago
A gear ratio is the ratio of the teeth on the front sprocket and the teeth on the rear sprocket. If a bike has 36 teeth on the f
earnstyle [38]
36:12. 36 is the teeth on the front socket and 12 is the teeth on the rear socket. All you need to do is simplify by finding the greatest common factor (GCF) of 36 and 12-which is 12, then divide by the GCF. This gives you 3:1. The gear ratio for the bike is 3 teeth on the front socket for every 1 teeth on the rear socket (3:1)
3 0
3 years ago
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100 PTS!! PLEASE HELP! OVER DUE
Reika [66]

Answer:

-\frac{1}{2} \vec {c}

Step-by-step explanation:

Look at the component form of each vector.

Note that vector c is <4,4> and vector d is <-2,-2>

If one imagined the line that contained each vector, the line for both would have a slope of 1, because \frac{4}{4}=1=\frac{-2}{-2}

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector.  This means that there is some number "k", such that k \vec{c} = \vec {d}, or equivalently, kc_x=d_x and kc_y=d_y.

If kc_x=d_x and kc_y=d_y, we just need to substitute known values and solve for k:

kc_x=d_x\\k(4)=(-2)\\k=\dfrac{-2}{4}\\k=-\frac{1}{2}

Double checking that k works for the y-coordinates as well:

kc_y=d_y

(-\frac{1}{2}) (4)    ?    (-2)

-2=-2 \text{ } \checkmark

So, -\frac{1}{2} \vec {c} = \vec {d}

6 0
2 years ago
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