The answer is yes. I think that I’m right
The other endpoint is (1, -17).
The midpoint formula is:
![m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=m%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%20%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
Using our midpoint and endpoint, we have:
![(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2}) \\ \\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2} ](https://tex.z-dn.net/?f=%286%2C%20-11%29%20%3D%20%28%5Cfrac%7B11%2Bx_2%7D%7B2%7D%2C%20%5Cfrac%7B-5%2By_2%7D%7B2%7D%29%0A%5C%5C%0A%5C%5C6%3D%5Cfrac%7B11%2Bx_2%7D%7B2%7D%20%5Ctext%7B%20and%20%7D%20-11%3D%5Cfrac%7B-5%2By_2%7D%7B2%7D%0A)
For the first equation (to find the x-coordinate) we will multiply both sides by 2:
![6\times2=\frac{11+x_2}{2}\times 2 \\ \\12=11+x_2](https://tex.z-dn.net/?f=6%5Ctimes2%3D%5Cfrac%7B11%2Bx_2%7D%7B2%7D%5Ctimes%202%0A%5C%5C%0A%5C%5C12%3D11%2Bx_2)
Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂
For the second equation (the y-coordinate) we multiply both sides by 2:
![-11\times2=\frac{-5+y_2}{2}\times 2 \\ \\-22=-5+y_2](https://tex.z-dn.net/?f=-11%5Ctimes2%3D%5Cfrac%7B-5%2By_2%7D%7B2%7D%5Ctimes%202%0A%5C%5C%0A%5C%5C-22%3D-5%2By_2)
Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂
This means that (x₂, y₂) is at (1, -17).
X = arctan(32/19)
x = 59.30 degrees.
You don't say if the answer needs to be rounded, so round it as needed.
Answer:
34
Step-by-step explanation: