Optic fiber is the medium that is often used to transfer computer information
Answer:
Range of R is from 4.81MΩ to 36.54 MΩ
Explanation:
Capacitance(C) = 0.520 µF = 0.52 x 10^(-6) F
Time constant = from 2.5 to 19 seconds
In RC circuits, time constant is;
r = RC
Where R is the range (in MΩ)
And r is time constant
Thus,
R = r/c
So minimum range will be at 2.5seconds.
Thus; Rmin = 2.5/(0.52 x 10^(-6)) = 4.81 x 10^(6) Ω = 4.81MΩ
Rmax = 19/(0.52 x 10^(-6)) = 36.54 x 10^(6) Ω = 36.54 MΩ
Answer:
2.06 x 10⁴ J
Explanation:
The process takes place in three steps. First, the ice is heated from -20 °C to 0 °C. Then the ice undergoes a phase change to water. Finally, the water is heated from 0 °C to 50 °C.
The heat energy required for the first step is as follows:
Q = mcΔT = (36.0 g)(2.00 Jg⁻¹°C⁻¹)(0 °C - (-20 °C)) = 1440 J
The heat energy required for the phase change (where L is the heat of fusion) is then calculated. Grams are converted to moles using the molar weight of water (18.02 g/mol)
Q = ML = (36.0 g)(mol/18.02g)(6000 J/mol) = 11987 J
Finally, the heat energy required to raise the temperature of the water to 50°C is calculated:
Q = mcΔT = (36.0 g)(4.00 Jg⁻¹°C⁻¹)(50 °C - 0 °C) = 7200 J
Adding all of the heat energy values together gives:
(1440 + 11987 + 7200) J = 20627 J
The final answer is 2.06 x 10⁴ J
Answer:
The sum of PE and KE remains constant
Explanation: