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3 years ago

You move a 25 N object in 10s with 100 W of power. How far did you move the object?

Physics

1 answer:

sergejj [24]3 years ago

8 0

Answer:

Distance = 40 meters.

Explanation:

Given the following data;

Force = 25N

Time = 10 seconds

Power = 100 Watt

To find the distance;

First of all, we would determine the work done;

Workdone = power * time

Workdone = 100 * 10

Workdone = 1000 Nm

Next, we use the following formula to find the distance;

Workdone = force * distance

1000 = 25 * distance

Distance = 1000/25

Distance = 40 meters.

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Please help me on my physics hw

MatroZZZ [7]

Answer:

1. 11 A

2. 240 V

3. 8 Ω

4. 60 C

5. 14400 C

Explanation:

1. Determination of the current.

Voltage (V) = 110 V

Resistance (R) = 10 Ω

Current (I) =?

V = IR

110 = I × 10

Divide both side by 10

I = 110 / 10

I = 11 A

2. Determination of the voltage

Current (I) = 3 A

Resistance (R) = 80 Ω

Voltage (V) =?

V = IR

V = 3 × 80

V = 240 V

3. Determination of the resistance.

Current (I) = 0.5 A

Voltage (V) = 4 V

Resistance (R) =?

V = IR

4 = 0.5 × R

Divide both side by 0.5

R = 4 / 0.5

R = 8 Ω

4. Determination of the charge

Current (I) = 2 A

Time (t) = 30 s

Charge (Q) =?

Q = it

Q = 2 × 30

Q = 60 C

5. Determination of the charge.

We'll begin by converting 20 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

20 mins = 20 × 60

20 mins = 1200 s

Finally, we shall determine the charge as follow:

Current (I) = 12 A

Time (t) = 1200 s

Charge (Q) =?

Q = it

Q = 12 × 1200

Q = 14400 C

6 0

3 years ago

What is the resistance of 1.0 m of a solid cylindrical metal cable having a diameter of 0.40 inches and a resistivity of 1.68 ×

Dahasolnce [82]

Given;

redistivity =1.68/100000000W.m

diameter =0.40in

=0.01016m

length =1m

resistance =?

redistivity =resistance×area/lenght

restance=resistivity × length /area

so, resistance =1.6535/1000000 ohmn

8 0

3 years ago

Two objects moving with the same speed may not have the same velocity. Why?

Nutka1998 [239]

Objects have the same velocity only if they are moving at the same speed and in the same direction. Objects moving at different speeds, in different directions, or both have different velocities.

4 0

1 year ago

who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can pla

densk [106]

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Explanation:

3 0

3 years ago

Read 2 more answers

A 1-m3 tank containing air @ 25 oC & 500 kPa is connected to another tank containing 5 kg of air at 35 oC & 200 kPa thro

VladimirAG [237]

Answer:

Volume of Tank 2, V' = $2.17 m^{3}$

Equilibrium Pressure, $P_{eq} = 278.82 kPa$

Given:

Volume of Tank 1, V = 1 $m^{3}$

Temperature of Tank 1, T = $25^{\circ}C$ = 298 K

Pressure of Tank 1, P = 500 kPa

Mass of air in Tank 2, m = 5 kg

Temperature of tank 2, T' = $35^{\circ}C$ = 303 K

Pressure of Tank 2, P' = 200 kPa

Equilibrium temperature, $20^{\circ}C$ = 293 K

Solution:

For Tank 1, mass of air in tank can be calculated by:

PV = m'RT

$m' = \frac{PV}{RT}$

$m' = \frac{500\times 1}{0.287\times 298} = 5.85 kg$

Also, from the eqn:

PV' = mRT

V' = volume of Tank 2

Thus

V' = $\frac{mRT}{P}$

V' = $\frac{5\times 0.287\times 303}{200} = 2.17 m^{3}$

Now,

Total Volume, V'' = V + V' = 1 + 2.17 = 3.17 $m^{3}$

Total air mass, m'' = m + m' = 5 + 5.85 = 10.85 kg

Final equilibrium pressure, P'' is given by:

$P_{eq}V'' = m''RT_{eq}$

$P_{eq} = \frac{m''RT_{eq}}{V''}$

$P_{eq} = \frac{10.85\times 0.87\times 293}{3.17} = 287.82 kPa$

$P_{eq} = 287.82 kPa$

3 0

3 years ago