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inessss [21]
3 years ago
13

PLEASE HELP ME

Mathematics
1 answer:
Triss [41]3 years ago
8 0
2/3

There are 6 people at the table and 4 of them have names that start with m. So the fraction is 4/6 and that simplified is 2/3
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Find the value of 2a² + 5b² when a= -6 and b= 2
sashaice [31]
2(-6^2)+5(2^2)
2(36)+5(4)
72+20
92
4 0
3 years ago
Read 2 more answers
If a = -3, determine the value of 4a + 5+ 8a.<br> HELP PLEASE
Y_Kistochka [10]

Step-by-step explanation:

I4(-3)+5| +8(-3)

|-12+5| -24

7-24 = -17

3 0
3 years ago
in the school library there are 4850 Hindi and English books if the Hindi books are 42% find the number of English books in the
Marina CMI [18]

Answer:

2813 English books

Step-by-step explanation:

Hindi books are 42% of 4850

42 ÷ 100 = 0.42

0.42 × 4850 = 2037 Hindi books

number of English books = total number of Hindi and English books - number of hindi books

4850 - 2037 = 2813 English books

6 0
2 years ago
Determine if the series 3/4 + 4/5 + 5/6 is convergent or divergent ​
vodka [1.7K]

Answer:

DIVERGENT

Step-by-step explanation:

3 0
3 years ago
Please explain, thanks! :)<br><br> Multiply DE
Anit [1.1K]
First, we have to make sure that the number of columns in the first matrix is equal to the number of rows in the second matrix.

\left[\begin{array}{cc}1&-3&2&0\\\end{array}\right] *   \left[\begin{array}{ccc}2&3&4\\1&2&3\end{array}\right]

Since this is true, we can continue to solve the problem.
To multiply two matrices, multiply each row element in the first matrix by each column element in the second matrix. For example:
1*2 = 2
-3*1=-3
Then we add them to get our new matrix element.
-3+2=-1
Then we move to the next column of the second matrix.
1*3=3
-3*2=-6
-6+3=-3
Then the final column of the second matrix.
1*4=4
-3*3=-9
-9+4=-5
Our matrix so far:
\left[\begin{array}{ccc}-1&-3&-5\\x&x&x\end{array}\right]
We do the same for the bottom row of the first matrix.
<em>First Column</em>
2*2=4
0*1=0
4+0=4
<em>Second Column
</em>2*3=6
0*2=0
6+0=6
<em>Third Column</em>
2*4=8
0*3=0
8+0=8
Our final matrix is:
\left[\begin{array}{ccc}-1&-3&-5\\4&6&8\end{array}\right]

:)

8 0
3 years ago
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