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mash [69]
3 years ago
5

At the library, Herb spent hour looking for a book, 1 hour

Mathematics
2 answers:
Step2247 [10]3 years ago
6 0
3 hours lol. Just add 1 hour looking for a book. 1 hour reading. And 1 hour doing research. 1+1+1=3
avanturin [10]3 years ago
5 0

Answer:

3 hours obviously

Step-by-step explanation:

1 hour looking for a book, 1 hour reading it, and one hour doing research on the book = 3 hours

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Solve for z: yz + 4z = z - y²<br><br><br><br>​
poizon [28]

Answer:

Step-by-step explanation:

yz+4z=z-y²

yz+4z-z=-y²

yz+3z=-y²

z(y+3)=-y²

z=-\frac{y^2}{y+3 }

3 0
3 years ago
Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm
iragen [17]

Answer:

a. 0.691

b. 0.382

c. 0.933

d. $88.490

e. $58.168

f. 5th percentile: $42.103

95th percentile: $107.897

Step-by-step explanation:

We have, for the purchase amounts by customers, a normal distribution with mean $75 and standard deviation of $20.

a. This can be calculated using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\P(X

The probability that a randomly selected customer spends less than $85 at this store is 0.691.

b. We have to calculate the z-scores for both values:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{65-75}{20}=\dfrac{-10}{20}=-0.5\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\\\P(65

The probability that a randomly selected customer spends between $65 and $85 at this store is 0.382.

c. We recalculate the z-score for X=45.

z=\dfrac{X-\mu}{\sigma}=\dfrac{45-75}{20}=\dfrac{-30}{20}=-1.5\\\\\\P(X>45)=P(z>-1.5)=0.933

The probability that a randomly selected customer spends more than $45 at this store is 0.933.

d. In this case, first we have to calculate the z-score that satisfies P(z<z*)=0.75, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+0.67449\cdot 20=75+13.4898=88.490

75% of the customers will not spend more than $88.49.

e. In this case, first we have to calculate the z-score that satisfies P(z>z*)=0.8, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z>-0.84162)=0.80

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+(-0.84162)\cdot 20=75-16.8324=58.168

80% of the customers will spend more than $58.17.

f. We have to calculate the two points that are equidistant from the mean such that 90% of all customer purchases are between these values.

In terms of the z-score, we can express this as:

P(|z|

The value for z* is ±1.64485.

We can now calculate the values for X as:

X_1=\mu+z_1\cdot\sigma=75+(-1.64485)\cdot 20=75-32.897=42.103\\\\\\X_2=\mu+z_2\cdot\sigma=75+1.64485\cdot 20=75+32.897=107.897

5th percentile: $42.103

95th percentile: $107.897

5 0
4 years ago
Triangle A C B is shown. Angle A C B is a right angle. Altitude h is drawn from point C to point D on side A B, forming a right
monitta

Answer:

Answer B.) \sqrt[2]{70}

6 0
3 years ago
Read 2 more answers
Helppppp. Pleaseee? :(
mylen [45]
There isnt enough information to solve the question, answer is E.
5 0
3 years ago
Read 2 more answers
Look at the street map. What street intersects with Geary Street?
Vinvika [58]
A. Union Street

Hope This Helps!
8 0
3 years ago
Read 2 more answers
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