Answer:
Shifted by 6 units left on the x-axis.
Step-by-step explanation:
Given function is,
f(x) = 5ˣ + 1
After transformation, this function becomes g(x) = ![5^{(x+6)}+1](https://tex.z-dn.net/?f=5%5E%7B%28x%2B6%29%7D%2B1)
Here, g(x) = f(x + 6)
By the rule of transformation,
Function 'f' has been shifted by 6 units left on the x-axis to form a new function 'g'.
![\sf \longrightarrow \: f(x) = {x}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20f%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20)
Write the parent function in the standard form I.e.
![\boxed{ \tt \:y =a(x - h) \times 2 + k }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Ctt%20%5C%3Ay%20%3Da%28x%20-%20h%29%20%5Ctimes%202%20%2B%20k%20%20%7D)
Where,
![\sf \longrightarrow \:y= 1(x - 0)^{2} \times 2 + 0](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3Ay%3D%20%201%28x%20-%200%29%5E%7B2%7D%20%5Ctimes%202%20%2B%200)
![\sf \longrightarrow \: y = (x - 0) ^{2} \times 2 + 0](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20y%20%3D%20%28x%20-%200%29%20%5E%7B2%7D%20%20%5Ctimes%202%20%2B%200)
![\sf \longrightarrow \: y = {x}^{2} \times 2](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20y%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%5Ctimes%202)
![\sf \longrightarrow \: y = 2{x}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20y%20%3D%20%202%7Bx%7D%5E%7B2%7D%20%20)
((x2-x1),(y2-y1))
((6-5),(9-8))
Component form: (1,1)
(1^2+1^2)^(1/2)
Magnitude: (2)^(1/2)
Answer:
y=mx+b is slope-intercept form
where m is the slope and b is the y intercept.
Since the line crosses the y axis at 0,0 the intercept is +0 or just nothing.
now all we need to do is find the slope
to do that just go from the y intercept (the first point) y units up and x units over untill u cross at the next point. for examples from (0, 0) to (1, 8)-the next point- i need to go up 8 units up and 1 unit over. this is described as rise over run and that is your slope 8/1 rise/run. rise is how many units i go up (or down) from the y intercept until the next point that lies on the line and run is how far i need to go over from how many units i just went up. If u continue to go 8 up and 1 over from each point u will see that u get a point lying of the line. This is why 8/1 is your slope
8/1 is the slope and 0,0 is your y intercept so we put nothing
the equation is y=8x
Step-by-step explanation: