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polet [3.4K]
3 years ago
12

What is the slope of the line that passes through the pair of points? (4.7).(7,-2)

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

-3      i hope this helps :)

Step-by-step explanation:

(4,7)    (7,-2)

x1 y1    x2 y2

<u>-2 - 7 </u> = <u>-9</u> = -3

7  - 4      3

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Simplify the expression 5+(4+x)
photoshop1234 [79]
5 + 4x
I think that’s right
4 0
3 years ago
Read 2 more answers
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
After a 80% reduction, you purchase a new washing machine on sale for $56.
Daniel [21]
80% = $56
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100% = $70 * 100 = $700
Original price = $700
Hope this helps.
:-)
3 0
2 years ago
How much do u need to subtract from 41/6 to make 6
dem82 [27]
41/6-5/6 = 36/6
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4 0
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Can someone please solve this with steps
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185/5=37

37=x

6 0
3 years ago
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