8^2 + 5^2 = c^2
64 + 25 = c^2
89 = c^2
c = 9.43
x = 9.43 - 3
x = 6.43
I think the answer is
-5 < x<span> > 5
</span>
Answer:
yes they are
Step-by-step explanation:
see nobody answers correctly:)
Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
I = $1,200.00
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year,
then, solving our equation
I = 4000 × 0.06 × 5 = 1200
I = $1,200.00
